Math: 6÷2(1+2) = ? | |
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schiehallion User ID: 31138050 United Kingdom 12/30/2012 07:07 AM Report Abusive Post Report Copyright Violation | Brackets Orders Divide Multiply Add Subtract I'm going with 9. And so does Wolfram Alpha [link to www.wolframalpha.com] scottish, british, european but first of all Human. Even this is not true. I am Spirit appearing to be solid, just like all life everywhere |
MrPaul User ID: 31076171 South Africa 12/30/2012 07:16 AM Report Abusive Post Report Copyright Violation | You don't have to do brackets first, you can leave them for later. You just can't do much with them until you solve them, or for example use the distribution rule. Same with exponents. They are separate units of the problem and cannot interact with other parts of the problem. In most cases the best plan of attack simply is brackets, exponents, etc. Also, addition does not take precedence over subtraction (it is the same thing) and multiplication does not take precedence over division (same thing). Subtraction is just adding a negated number and division is multiplying an inverted number. So it should be PEMA, but better yet nothing and just an understanding of what parts of a problem can interact with each other and how. It is LEFT TO RIGHT otherwise the meaning of subtract and divide changes. If you don't have subtract/divide the order doesn't matter either! Addition/subtraction is on a higher level than multiply/divide simply by convention so we save on the number of brackets we need to use. So... if you want to do the distributive thing you need to do 6/2 first: 3*(1+2) = 3 + 6 = 9 ! The problem is a trick because it intuitively (for me at least, at first glance) made me see 6/(2(1+2))=1. Somehow the omission of the * operator glues the 2 tighter to the (1+2) than it should... or perhaps that is a very valid convention too.. implicit brackets around a multiply without the * operator...? These are CONVENTIONS to allow for single line equations. If you work with multi line equations there is no confusion: 6 ------- = 1 2*(1+2) 6 - * (1 + 2) = 9 2 Of course if you use a different convention then you are also right! Last Edited by Deplorable Me on 12/30/2012 07:19 AM |
Anonymous Coward User ID: 31098667 United States 12/30/2012 07:39 AM Report Abusive Post Report Copyright Violation | Order of operations in arithmetic is like grammar in language. See how many people think conventions have nothing to do with the expression of thought - as if rules somehow stifle the possibility of actually getting their point across, or misuse is somehow more creative. It is easy to see, in a simple equation, the resulting confusion. A careful mathematician would avoid writing something like that without specifying the protocols. Imagine a course in Creative Accounting. The goal, of course, would not be self expression. It would be to create profit. |
Anonymous Coward User ID: 19505114 Australia 12/30/2012 07:50 AM Report Abusive Post Report Copyright Violation | Alright, there's a lot of self-proclaimed experts around these parts. Let's see how your logic holds up against some basic mathematics. Quoting: Syrius 6÷2(1+2) = ? I'll give two hints. This is NOT a trick question, and there is only 1 correct answer. All tools used for computation are fair game. (Yes, I saw this somewhere else and decided to post it here.) Best of luck to all you geniuses . 4.5.... parentheses (1+2)=3+6=9 divided/2=4.5 |
Very easy User ID: 21495402 Canada 12/30/2012 03:45 PM Report Abusive Post Report Copyright Violation | Actually this is wrong.... The correct term for the order of operations is not PEDMAS it is BEDMAS which stands for: Brackets,Exponents,Divison,Multiplication,Addition, Subtraction so the solution would be 6/2(1+2) Do brackets first: 6/2(3) then exponents: there isnt any so this step can be skipped then division: 6/2(3)= 3(3) then multiplication 3*3=9 so the answer is 9 so for 2+3*(0-2(6-5)) would equal, starting with the left bracket first: 2+3*(-2(1))= 2+3*(-2)= 2 + (-6)= the answer is -4 |
ncbc User ID: 31275122 United States 01/01/2013 11:30 AM Report Abusive Post Report Copyright Violation | there are (3) mathematical equations to be solved in this problem. First, you must do the equation in parentesis (1+2). This can only equal 3. So you move to the left. Then by moving left, the Second equation to be solved is the multiplication (2 x (1+2)). This can only equal 6. Finally, the third equation to be solved includes dividing the previous solution of the first two equations (as denominators) into 6. That leaves the equation to be solved as (6 divided by 6) Therefore, the answer to this problem can only be 1; NOT 9. No wonder our kids are failing math in school. |
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Anonymous Coward User ID: 30992481 United States 01/01/2013 01:01 PM Report Abusive Post Report Copyright Violation | NO look! [link to en.wikipedia.org] Actually this is wrong.... The correct term for the order of operations is not PEDMAS it is BEDMAS which stands for: Quoting: Very easy 21495402 Brackets,Exponents,Divison,Multiplication,Addition, Subtraction so the solution would be 6/2(1+2) Do brackets first: 6/2(3) then exponents: there isnt any so this step can be skipped then division: 6/2(3)= 3(3) then multiplication 3*3=9 so the answer is 9 so for 2+3*(0-2(6-5)) would equal, starting with the left bracket first: 2+3*(-2(1))= 2+3*(-2)= 2 + (-6)= the answer is -4 |
caper26 User ID: 32057798 Canada 01/13/2013 12:36 AM Report Abusive Post Report Copyright Violation | First I will explain. I didn't any of the previous posts, no need. Here is what you do: Distribute 2 into the parentheses. Why? because it is a factor of the original terms INSIDE them, and cannot be ripped apart. I will show you why: 6 = 4+2 = 2(2+1) = 2(3) The 2 is a common factor of 4 & 2. No matter which way you view it, the value 6 MUST maintain its value. Just as you cannot take the 4 from (4+2) and divide it into a number with the "+ 2". I cannot take the 2 from 2(2+1) and divide it into another number without the (2+1). You ARE allowed to distribute before division, or any other operator, since you are allowed to simplify any equation first. There are MANY references which state "Remove parentheses by distribution" Try Googling that as a search term. 6÷2(2+1) = 6÷(4+2) = 1 Now, some people have argued that you don't NEED to distribute the 2; you just add the 2+1, and end up with 2(3). Then they go on the say that this is the same as 2*(3). WRONG! You STILL have parentheses and STILL need to distribute that 2 inside them, for the reasons discussed about factoring above. Therefore you have this: 6÷2(3) and must distribute like this: 6÷2(3+0) = 6÷[2(3) + 2(0)] = 6÷6 = 1 These people who get 9 try and rip the 2 away from the parentheses by inserting a times symbol like this: 6÷2*(3), and then do the division of 6÷2 first. I explained the illegalities of doing this, since the 2 is a factor of the 2+1. Lastly, 6÷2 is NOT (6/2), as in (6/2)(2+1). This is totally incorrect, since it lacks that parentheses in the original equation. Check any online or written text. Leading fractions as a coefficient ALWAYS have ( ) around them. I hope this clears things up. Regards. |
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Anonymous Coward User ID: 29804770 United States 01/13/2013 01:38 AM Report Abusive Post Report Copyright Violation | Some of you need practice as badly as I did, I got a spark for engineering a few months back so I've been doing a lot of math lately. A really good place to practice is [link to www.khanacademy.org (secure)] and don't forget the math tricks [link to www.youtube.com] |