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The equation of a road is: 
ax^2 from A to B
R(x) { 
bx + c from B to C
B is 1000 feet horizontally from A and 100 feet higher. Since the road is smooth, R'(x) is continuous. What is the value of B?

I think it involves some differentiation.. but I don't really know what to do. The options for answers are:

a) .2
b) .02
c) .002
d) .0002
e) .00002

??????????????????????????????????????????????????
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How can I help you with your misunderstandings of the universe?
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SOOOoooooo    When in doubt pick C....Come on OP.....

The answer to this question depends on the relationship between the points x, A, and B. I am assuming that point A is at the origin, which is consistent with the expression for R(x), and the coordinates of point B would be (1000, 100). We have the equation
100 = R(1000) = a(1000)^2
= 1000000a
Solving for a gives
a = 0.0001

Because the derivative is also continuous, we also know that
(ax^2)' = (bx + c)' at x = 1000
or 2ax = b at x = 1000
So b = 2(0.0001)*1000
= 0.2

OP :lihvlcdxuxluxggh:
[/quote]
 Wow, you must have gone to college. Congratulations. Now ask me a question.
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I deserve none of your intellect....I have my own....

:ljvlc;c;t;ctu;ut:
[/quote]
It must have cost a small fortune to get that mind. I underestimate your dedication to the ignorant.
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Original Message 5 beers In, i am channeling an eternal spirit ask me a question.

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