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04:09 AM
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Only for geniuses!
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[quote:Anonymous Coward 17260532:MV8yNDExNjc0XzQxMzU1NTc0XzJEODBDQ0Ux] [quote:Anonymous Coward 27582823:MV8yNDExNjc0XzQxMzU1MzU2X0Y1MzVCM0ZE] Reminder for new page and new comers. Correct answers so far If f(2)=12, f(3)=12, f(4)=20, f(5)=30, f(6)=42, define f(n) and give f(9) a) f(n)=n*(n+1) so f(9)=9*10=90 b) with [n] = nth prime number, f(n)=[n]+[2n-2] so f(9)=[9]+[2*9-2]=23+[16]=23+53=76 c) f(n) = n * ((n+1) modulo 10)) so f(9) = 9 * (10 modulo 10) = 9 * 0 = 0 There is also a strange cabal which insist saying 72 is correct but failing to define f(n). [/quote] you god damn french man doing things all long and drawn out and shit.. whats with all the algebraic non-sense.. couldn't you just see the pattern at a first glance or what? [/quote]
Original Message
I don't know if this has been posted before. There is a math problem (joke?) that has been stirring a debate. Originated on Facebook and driving some crazy lol.
Can any of you on here come to the solution for this pattern(Pi?AR?). And if this has been answered what is the correct one? Thanks!
IF: 2=6
3=12
4=20
5=30
6=42
Then:9=??
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