Math: 6÷2(1+2) = ?

I will read it in a sec. I have researched the exact meaning of the obelus, depicted here:

[link to www.freeimagehosting.net]

It was used as a grouping symbol. Not that is applies anymore, it was first used like this:
6 ÷ 2 + 1 really meant 6 ÷ (2+1). neither here nor there, but I thought you would find that interesting, i guess.

I will read it in a sec. I have researched the exact meaning of the obelus, depicted here:

[link to www.freeimagehosting.net]

It was used as a grouping symbol. Not that is applies anymore, it was first used like this:
6 ÷ 2 + 1 really meant 6 ÷ (2+1). neither here nor there, but I thought you would find that interesting, i guess.

That is hilarious. He referenced the exact page of the book I found earlier this week.
But again, if you go back to that algebra page I gave you, we group variables together, and even YOU did those math equations using those very same rules, yet you are using a different 'rule' to get your 9, therefore, contradicting yourself.
Anyway, I gotta run for now. Sorry for a few snappy remarks at you earlier, I thought you were one of the other guys trolling, then I realized it was you after I replied :D

Do you have a source for that image?

All good I gave really shitty responses to people in this thread. Joke is on me, I was wrong. Thanks for your work.

If you have anything else on the obelus, post it here.

I made it. If you look at your screen at an angle, you should see caper_26 as a watermark

I have already, and of course, I was told I was retarded, etc etc.

I have already, and of course, I was told I was retarded, etc etc.

Yup. That was me. Sorry. You were right. I am retarded.

I am surprised you accept the obelus as the deal breaker, and not the identity property.
a / 1a = 1. This is not disputable. Even ask your PhD friend about that. the 1 is there whether you write it or not. Anyone who knows math knows this. Therefore a/a is always 1, and a/1a is always 1. Therefore a/2a MUST be 1/2, and 6/2a is 3/a, and a = 2+1 so 6/2(2+1) = 3/(2+1).

The identity law is something we all can read, and accept. For me, that was deal breaker, along with fractional coefficients written with a '/' all use ( ) as well.

I am surprised you accept the obelus as the deal breaker, and not the identity property.
a / 1a = 1. This is not disputable. Even ask your PhD friend about that. the 1 is there whether you write it or not. Anyone who knows math knows this. Therefore a/a is always 1, and a/1a is always 1. Therefore a/2a MUST be 1/2, and 6/2a is 3/a, and a = 2+1 so 6/2(2+1) = 3/(2+1).

The identity law is something we all can read, and accept. For me, that was deal breaker, along with fractional coefficients written with a '/' all use ( ) as well.

I understand, but the original equation was written with an obelus, NOT a solidus...

Obelus: The obelus is primarily used as a symbol for division
Slash: Used between numbers slash means division, and in this sense the symbol may be read aloud as "over".
Solidus: The solidus <snip due to html coding of symbols> or a shilling mark is a punctuation mark used to indicate fractions.
Now, the obelus and slash can be used interchangeably as long as the slash is interpreted as division NOT mistaken for a solidus.
In that regard 6÷2n = 6/2n, which MEANS 6/(2n). Let n = 2+1.

So how did it go?

The 9 way or 1.

Somebody has to put this to vote.

But the identity law doesn't change, and is used the same way.


a ÷ a = 1 (There is still a 1 in front of both a's)
1a ÷ 1a = 1 (not 1*a÷1*a)

therefore, 6 ÷ 2n = 3/n

PS: The obelus can be interchanged with a divisional slash, but not as a Solidus. Check this out, forgot I had it:

===================================

Holy Shit!!

126 pages for a math problem???

What the hell???

Who gives that much of a shit??

It's 1.

Did anyone else catch the bold part in the OP?

I was a prick and an adamant 9er... caper_26 turned me into a 1er...

I obviously need to brush up on basic mathematical properties...

Funny, i was a 1'ner turned 9.

Gotta run dude, work in the a.m.

Here is another problem that tried to depict the problem in real world: you may agree or disagree with. Keep in mind, the units are "units squared" as we are dealing with area, so the units when the computation is done, must make sense:

[link to i45.tinypic.com]

Talk to you later man.

Did anyone else catch the bold part in the OP?

it could also be 1

[link to www.basic-mathematics.com]

Copy and paste it into this math solver webpage.
See what the computer tells you the answer is.

6÷2(1+2)=y

You could sub all of these for variables:
6÷2*(1+2)=y

You always do bracket first (that IS the rules).
Thus it becomes:
6÷2*(3)=y
6÷2*3=y

I think we can all agree on that.

OK.............


Now let's sub these with some variables:
6÷2*3=y

n will now mean 3:
6÷2*n=y

Which becomes:
6÷2n=y

Let's rearrange to put all variable on one side.
6=2ny

Now let's solve for ny
6÷2=ny
3=ny

Now let's swap n back with a 3.
3=3y

Now let's solve for y.
3=3y
3÷3=y
1=y

I still get my same answer (because I followed the proper math-rules).