Math: 6÷2(1+2) = ?

I don't think math has different rules, math is universal. I'm not math expert and didn't do well in any math courses, but I'm interested in mathematics for what it is.

It makes me wonder if humans invested math or if math is an objective part of the universe.

Wrong! You don't do 2*3. 6/2 first. Then multiply that by 3.

2+3*(0-2(6-5)) = -4

2+3*(0-2(1))

2+3*(0-2)

2+3*(-2)

2+(-6)

-4

Math is a universal language. It is based on logic and reason. If you were to be abducted by aliens start writing down Mathematics using any means possible, that would show that intelligence and then you could actually convey a message and start building a common language. All thanks to Math

Wait You are right My bad. Sorry apparently PEMDAS is just stupid and my high school teachers are fucking retarded.
and yeah its -4.
Can you figure this one out? [link to thinkzone.wlonk.com]

Isn't 6÷2(1+2) the same as saying 6 is divided by everything behind the division symbol such as: 6/2(1+3)

6
___ =

2(1+3)

6
___
2(3) or 2*3

6
_ = 1

6

If you are getting the answer 9, it seems that you are forgetting to simplify. For example: 6÷2*3 is not 3*3, it's 3÷3 or 3/3. When you look at it as a fraction, it should become easier.

6÷2(1+2)same as 6/2(1+2)
6÷2*3 same as 6/2*3
6÷6 same as 6/6. Note: You don't divide 6 by 2 first. Multiply 2 and 3 first then divide. Order of operation still apply.

If you are getting 12 or -4, I don't know what the fuck you are doing.

2

9

is this why the economy is fucked?

6÷2(1+2)

6/2(3)

6/2*3

1

That´s basic math.

Let me call my uncle, he's good at math.

Can some one give me some cliffs? I don't want to read 90+ pages to figure this out.

[link to www.wolframalpha.com]

Brackets Orders Divide Multiply Add Subtract



I'm going with 9.
And so does Wolfram Alpha

[link to www.wolframalpha.com]

PEMDAS / BODMAS / whatever is just wrong...

You don't have to do brackets first, you can leave them for later. You just can't do much with them until you solve them, or for example use the distribution rule.

Same with exponents. They are separate units of the problem and cannot interact with other parts of the problem. In most cases the best plan of attack simply is brackets, exponents, etc.

Also, addition does not take precedence over subtraction (it is the same thing) and multiplication does not take precedence over division (same thing). Subtraction is just adding a negated number and division is multiplying an inverted number.

So it should be PEMA, but better yet nothing and just an understanding of what parts of a problem can interact with each other and how.

It is LEFT TO RIGHT otherwise the meaning of subtract and divide changes. If you don't have subtract/divide the order doesn't matter either!

Addition/subtraction is on a higher level than multiply/divide simply by convention so we save on the number of brackets we need to use.

So... if you want to do the distributive thing you need to do 6/2 first:
3*(1+2) = 3 + 6 = 9 !

The problem is a trick because it intuitively (for me at least, at first glance) made me see 6/(2(1+2))=1. Somehow the omission of the * operator glues the 2 tighter to the (1+2) than it should... or perhaps that is a very valid convention too.. implicit brackets around a multiply without the * operator...?

These are CONVENTIONS to allow for single line equations. If you work with multi line equations there is no confusion:

6
------- = 1
2*(1+2)


6
- * (1 + 2) = 9
2

Of course if you use a different convention then you are also right!



Last Edited by MrPaul on 12/30/2012 07:19 AM

Order of operations in arithmetic is like grammar in language. See how many people think conventions have nothing to do with the expression of thought - as if rules somehow stifle the possibility of actually getting their point across, or misuse is somehow more creative.

It is easy to see, in a simple equation, the resulting confusion. A careful mathematician would avoid writing something like that without specifying the protocols.

Imagine a course in Creative Accounting. The goal, of course, would not be self expression.
It would be to create profit.

4.5.... parentheses (1+2)=3+6=9 divided/2=4.5

Actually this is wrong.... The correct term for the order of operations is not PEDMAS it is BEDMAS which stands for:

Brackets,Exponents,Divison,Multiplication,Addition, Subtraction

so the solution would be

6/2(1+2)

Do brackets first:
6/2(3)

then exponents:
there isnt any so this step can be skipped

then division:
6/2(3)=
3(3)

then multiplication
3*3=9

so the answer is 9

so for 2+3*(0-2(6-5)) would equal, starting with the left bracket first:

2+3*(-2(1))=
2+3*(-2)=
2 + (-6)=


the answer is -4

there are (3) mathematical equations to be solved in this problem. First, you must do the equation in parentesis (1+2). This can only equal 3. So you move to the left. Then by moving left, the Second equation to be solved is the multiplication (2 x (1+2)). This can only equal 6. Finally, the third equation to be solved includes dividing the previous solution of the first two equations (as denominators) into 6. That leaves the equation to be solved as (6 divided by 6) Therefore, the answer to this problem can only be 1; NOT 9. No wonder our kids are failing math in school.

If you didn't answer 1 you're clinically retarded...

badly written expression...

1





please excuse my dear aunt sally!!!!

NO




look!
[link to en.wikipedia.org]

First I will explain. I didn't any of the previous posts, no need. Here is what you do:
Distribute 2 into the parentheses. Why? because it is a factor of the original terms INSIDE them, and cannot be ripped apart. I will show you why:
6 = 4+2 = 2(2+1) = 2(3) The 2 is a common factor of 4 & 2.
No matter which way you view it, the value 6 MUST maintain its value. Just as you cannot take the 4 from (4+2) and divide it into a number with the "+ 2". I cannot take the 2 from 2(2+1) and divide it into another number without the (2+1).
You ARE allowed to distribute before division, or any other operator, since you are allowed to simplify any equation first. There are MANY references which state "Remove parentheses by distribution" Try Googling that as a search term.
6÷2(2+1) = 6÷(4+2) = 1
Now, some people have argued that you don't NEED to distribute the 2; you just add the 2+1, and end up with 2(3). Then they go on the say that this is the same as 2*(3). WRONG! You STILL have parentheses and STILL need to distribute that 2 inside them, for the reasons discussed about factoring above. Therefore you have this:
6÷2(3) and must distribute like this:
6÷2(3+0) = 6÷[2(3) + 2(0)] = 6÷6 = 1
These people who get 9 try and rip the 2 away from the parentheses by inserting a times symbol like this:
6÷2*(3), and then do the division of 6÷2 first. I explained the illegalities of doing this, since the 2 is a factor of the 2+1.
Lastly, 6÷2 is NOT (6/2), as in (6/2)(2+1). This is totally incorrect, since it lacks that parentheses in the original equation. Check any online or written text. Leading fractions as a coefficient ALWAYS have ( ) around them.
I hope this clears things up.
Regards.

6
____
2(3)

6
_ -> 3
2

1 3
- <- -
2 6

First time seeing this and I'm not a number fucker but these answer is clearly 9 why is there so many pages.... Bunch a fuckin dummies out there

(1/2(6)3), 1|3 <-> 2|6

6
_ -> 1
6

1 1
- -> -
6 6

(1/6(6)1), 1|1 <-> 6|6