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Message Subject Math: 6÷2(1+2) = ?
Poster Handle Anonymous Coward
Post Content
6 ÷ 2(1+2) = 6 ÷ [2(2) + 2(1)] = 6 ÷ (4+2) = 1

or,

z = 6
a = 2
b = 1

z ÷ a(a+b) = z ÷ (a^2 + ab) = 6 ÷ (2^2 + 2*1) = 6÷(4+2) = 1
 Quoting: Anonymous Coward 32057798


Order of operations is wrong.

You're using the second mulitplication before the first division.

Math is simply not truly applied.
 
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