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05:19 AM

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Message Subject Math: 6÷2(1+2) = ?
Poster Handle Anonymous Coward
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All good I gave really shitty responses to people in this thread. Joke is on me, I was wrong. Thanks for your work.

If you have anything else on the obelus, post it here.
 Quoting: Anonymous Coward 31557420

I have already, and of course, I was told I was retarded, etc etc.
 Quoting: caper_26 32057798

I am surprised you accept the obelus as the deal breaker, and not the identity property.
a / 1a = 1. This is not disputable. Even ask your PhD friend about that. the 1 is there whether you write it or not. Anyone who knows math knows this. Therefore a/a is always 1, and a/1a is always 1. Therefore a/2a MUST be 1/2, and 6/2a is 3/a, and a = 2+1 so 6/2(2+1) = 3/(2+1).

The identity law is something we all can read, and accept. For me, that was deal breaker, along with fractional coefficients written with a '/' all use ( ) as well.
 Quoting: Anonymous Coward 32057798

I understand, but the original equation was written with an obelus, NOT a solidus...
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