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## Pretty Good [** Nibiru / ELEnin **] Debunk Post I Saw Today | |

Practically ETOffer Upgrade User ID: 1375940 United States 08/05/2011 05:20 PM Report Abusive Post Report Copyright Violation | Long story short... If Nibiru exists, it's NOT a normal planet. The only way this thing could be real is if it's a 'planetary vessel' (planetary spaceship) that can travel faster than the speed of light.I have always considered this possibility in my head, because of the fact no astronomer has been able to spot it... Besides the IRAS if you choose to believe that. - - - - - - - - - - - - - - - Firstly, though it is said that Nibiru is larger than Jupiter, let us be nice and just say that Nibiru is identical in mass to Jupiter- 1.8986*10^27 kilograms. If it were larger, things would be even worse for the Nibiru proponents. Second, the mass of the sun is 1.9891*10^30 kilograms. Now, let us think about how much force this would entail being applied between the sun and Nibiru at the perigee of Nibiru’s orbit, which is about 1 AU (150 million km) in distance. The formula used derive how much force two objects are applying on each other by gravity is F=G({m1*m2}/r^2), where G is the gravitational constant (6.67*10^-11) m^3 * kg^-1 * s^-2). Below I will omit the units for the sake of clarity. The m^3 and the km cancel to produce kg/s with a difference to the exponents of -3 (in case you read the math below and were looking for the three missing digits). So, let us plug in the numbers: F=G({m1m2}/r^2) F=[6.67*10^-11 * ({1.8986*10^27} * {1.9891*10^30})]/(150,000,000^2) F=(2.51896*10^45)/(2.25*10^16) F=1.1952*10^44 N/s That’s 119520000000000000000000000000000000000000000 Newtons of force every second between Nibiru and the sun at its orbit. But then you might ask, when objects slingshot around the sun, they move quite quickly, which is how they escape. After all, that is how comets escape, right? Exactly right. Of course, comets do not have the added burden of being thousands of times the mass of our own planet, but that is exactly how they escape- they reach “escape velocity,” or, the speed required to escape a gravity well. So how fast would an object the size of Nibiru, moving in an elliptical orbit, be required to be traveling in order to escape the sun? The formula for escape velocity is Vsec=[2*G*M/r]^1/2, or, the square root of [2*G*M/r] where G is the gravitational constant, M is the mass being dealt with, and r is the radius of a circle whose diameter is the distance between the objects. Our G is 6.67*10^-11. Our M is extracted from the N-M/kg from the first formula, so, 1.1952*10^44. Our r is 1/2AU, so about 7.5*10^10 km. Vsec=[2(6.67*10^-11)*(1.1952*10^44)/(7.5*10^10)]^(1/2) Vsec=({1.5994*10^34}/{7.5*10^10})^(1/2) Vsec=(2.2126*10^23)^(1/2) Vsec=1.487*10^7 km/sec. This means that Nibiru’s escape velocity must be 14,870,000 kilometers per second. To put this utter absurdity into perspective, this is NEARLY SEVEN TIMES THE SPEED OF LIGHT! If Nibiru were ever travelling even a tiny fraction of that speed, tidal forces would tear it apart. Its wake would vaporize the inner planets. Welfare won't fix poverty. |

Practically ET (OP)User ID: 1375940 United States 08/05/2011 05:27 PM Report Abusive Post Report Copyright Violation | |

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