Calculating the diameter of Elenin from latest video

WHAT ARE SAYING THIS ?

Guess OP's calculator broke.

ok we are going to find out how big "comet" Elenin really is

the first thing we have to do is calculate the angle in degrees of Mercury as viewed from STEREO B

since we know the distance is about 1.5 AU, then the distance of STEREO B to Mercury is 93,000,000 x 1.5 = 140,000,000 miles

ok I found an online calculator:

[link to www.carbidedepot.com]

ok I found the online angle calculator

[link to www.1728.org]

ok we first click on find the angle tab

we enter the Distance of 140 million miles 140000000 (distance of STEREO B to Mercury)

we enter the size in same units 3032 miles (size of Mercury)

we calculate the angle

it is 0.0012409 Degrees

everyone got that?

now we have the angle to Mercury which is 0.0012409 Degrees

so since ELenin is about 10% of the apparent diameter of Mercury its angle is 10% of 0.0012409 Degrees

so the angle to ELEnin is 0.10 times 0.0012409 Degrees =

0.00012409 Degrees

everyone got that?

So how big do you calculate it is?

Are you saying that Elenin is 303.2 miles in diameter?

Last Edited by Ozicell on 09/02/2011 02:57 AM

so going back to our online calculator

[link to www.1728.org]

we have to recalculate the angle in seconds

Distance = 140,000,000 miles

Size (diameter) = 3,032 miles

angle in seconds = 4.4671 Seconds

since Elenin is 10% of that, the observed angle of Elenin is 0.10 x 4.4671 Seconds = 0.44671 Seconds

the distance is 40% of 140,000,000 miles or 56,000,000 miles

we enter that data

and we get 121 miles wide

so I get Elenin's diameter at 121 miles wide

give me a minute to check the calculations

that's in the ballpark

if I change the ratio of Elenin to Mercury to 35%

the distance would be 140,000,000 times .35

or 49000000 miles

I then get a diameter of 106 miles

not bad for an artificial spacecraft

If these figures are any where near accurate - it's WAAAYY bigger than they've been telling us!

agreed, didn't they say 3-5 km width?

we need a real physicist, astronomer, TBAR, Hoagland or whoever to do the math

and why is it no scientist on the entire planet of seven billion souls is doing this calculation?

one thing for sure is that object isn't 4x the size of Jupiter,so it can't be Nibiru

But your calculations are based on the apparent size of Elenin, and the apparent size of Elenin include coma. The diametre should be much, much more than 106 miles.

It is interesting that now it's so close yet we still don't know its correct size.

The pics and videos I've seen taken from Stereo Behind are not showing any coma or tail at all.

so right now there are 1,356 GLP users online

so c'mon GLPers, there has got to be a math whiz or nerd who can do these calculations more accurately

Elenin is almost to Mercury orbit, we have nice videos of it, we ought to be able to get a fairly accurate size of it

AND we ought to be able to calculate its mass

Terral says it has great mass because its speed is planetary speed

so lets calculate the speed of Elenin and compare it to comets that come inside of earth's orbit

how do we do this? We know the mass of the sun, we can get Elenin's velocity from the JPL ephemeris,so if we know those two then we should be able to calculate the mass

I agree - the Stereo pics and movies show it pretty clearly now and the exact distance between the stereo camera and Elenin must be known! This being the case, surely those who know how to calculate these things would be able to do it quite accurately by now.

absolutely no coma or tail except for that tetrahedral force field when the Sun's CME went across, check out his jpg image of it:

[link to projectcamelotproductions.com]

[link to www.Gas_oven.com]

Already seen it and thought it was quite interesting!

Last Edited by Ozicell on 09/02/2011 03:34 AM

I agree that we don't see tail, but you can't say that we don't see coma as there's no means of recognizing Coma or Nucleus...
For the tail, what's the direction of Elenin in relation with Stereo ? the tail could be behind it, on the axe Elenin/Stereo.

Isn't the tail always pointing away from the sun? Those pice and vids from stereo should have seen it if it was there! I may be wrong though, not sure.

Hey man 2nd link isn't working. Bad link?

Hmm, yes, you're probably right.
In fact, I think that there're usually 2 tails, one pointing away from the sun, and one pointing away from the direction of the comet.

graphic of comet tails:

[link to upload.wikimedia.org]

article on comet tails:

[link to spaceguard.rm.iasf.cnr.it]

[link to www.beugungsbild.de]

now take a look at this very short youtube video of Elenin interacting with a coronal mass ejection:

clearly Elenin has NO COMA and NO TAIL but has some sort of force field, two dumbbell shaped fields extend left and right as the CME crosses, the nucleus projects a tetrahedral shape:

elenin a closer look (8/25/2011)

[link to www.youtube.com]

STEREO B (behind earth orbit) is looking at Elenin toward Mercury with the Sun 90 degrees to the left

thus STEREO B would have a perfect view of a tail, if there was one, but there isn't

elenin a closer look (8/25/2011)

[link to www.youtube.com]

I saw a calculation last week that agrees basically with this. Even NASA does not say 4 kilometers anymore.

Good job OP!

The coma is a bigger measurement, but the coma comes and goes becasue it is a ship.

Its the infrared energy field has been judged 4x Jupiter in size. This is what can rock our little world!

Everyone needs to watch this short closeup video of Elenin:

Thread: Awesome closeup video of Elenin

[link to www.youtube.com]

No. That is not how to obtain the size. First off, all you are seeing is coma. There is only the faintest hint of a tail. The reason the tail is not obvious is that the tail is very faint and the instrument wasn't designed to look at objects that faint.

You cannot use Mercury as a ruler. Mercury is bright and is overexposed. It is CCD bleeding that you are seeing.

To get the actual size you first need to know the band. SECCHI has two bands, HI1 and HI2. The video doesn't say which one. The HI1 band as a per pixel resolution of 35 arcseconds. The HI2 band has a per pixel resolution of 240 arcseconds.

Now all you do is count pixels. This is hard from the image since it looks like the beacon image that was zoomed. On Aug 14/15 Elenin was about 1.3 AU from Earth and down to 1.0 AU on the 29th. It kind of looks to me to be 5 pixels across. It would be best to go back to the high resolution images. That means Elenin's coma (and it really is the coma) is 5 * 35 arcseconds across. Or 0.048 degrees. In radians that is 0.00085. To get the size multiple the size in radians by the distance giving you 0.0011 AU. In miles that is 102,000 miles. This is a reasonable size coma for a small comet. Comet Hale-Bopp had a coma over 1 million miles across.

Even with a 102,000 mile coma, Elenin is going to miss us by 0.23 AU, or 21 million miles. SO no danger from the coma.