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Menow
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02/25/2013 06:33 PM
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You talk about an "angle on the terminator this time of year" as if the moon's orientation in the sky doesn't change from one hour to the next.
 Quoting: Menow 636186


At moonrise a very precise angle of the terminator should be easy to calculate at any given location and date. THIS IS IS PRESENTLY NOT THE CASE. As a person who has spent my whole 52 years observing nature, I know the patterns pretty well
 Quoting: Anonymous Atrophysicist 1391715


By the way... what is wrong with the calculations already presented, here, just a page or so back?
Anonymous Atrophysicist
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02/25/2013 06:40 PM
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And yet given the choice of providing a counter argument to either one, you fail to come up with anything....

 Quoting: Menow 636186

Arguing with stupid idiot is the folly of fools, you cannot win.
By the way, I didn't "deny it happened" at all.
 Quoting: Minnow dick

You haven't said anything. It is amazing how shills can post pages of posts and never say a single thing you can pin them down with. If you aren't denying it, what is your point?


I simply challenged you to provide evidence showing what you claim took place. Funny how you can't do that-
 Quoting: Minnow dick

Actually I can, as I said there are literally hundreds of people and perhaps two dozen threads on this subject on this forum alone.I also provided a link to website earlier that clearly showed images that illustrate the effect, apparently you "missed" them?
Anonymous Atrophysicist
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02/25/2013 06:45 PM
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You talk about an "angle on the terminator this time of year" as if the moon's orientation in the sky doesn't change from one hour to the next.
 Quoting: Menow 636186


At moonrise a very precise angle of the terminator should be easy to calculate at any given location and date. THIS IS IS PRESENTLY NOT THE CASE. As a person who has spent my whole 52 years observing nature, I know the patterns pretty well
 Quoting: Anonymous Atrophysicist 1391715


By the way... what is wrong with the calculations already presented, here, just a page or so back?
 Quoting: Menow 636186


It is impossible to get a horizontal terminator at moonrise any time of year south of the 60the latitude unless it is a lunar eclipse. It's basic math. 23 degrees of "tilt is the maximum possible deviation from vertical due to the tilt of the axis of the earth and the declination of the moons orbit from the ecliptic of 5 derees added to the latitude gives us the maximum angle from vertical the terminator can portend at moonrise.
Menow
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02/25/2013 06:50 PM
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And yet given the choice of providing a counter argument to either one, you fail to come up with anything....

 Quoting: Menow 636186

Arguing with stupid idiot is the folly of fools, you cannot win.
By the way, I didn't "deny it happened" at all.
 Quoting: Minnow dick

You haven't said anything. It is amazing how shills can post pages of posts and never say a single thing you can pin them down with. If you aren't denying it, what is your point?
 Quoting: Anonymous Atrophysicist 1391715


I asked you to show evidence proving that the "anomaly" you want someone to explain actually took place. That's my simple and obvious point. What is there to "explain" if you don't show wtf you are even talking about?

I simply challenged you to provide evidence showing what you claim took place. Funny how you can't do that-
 Quoting: Minnow dick

Actually I can, as I said there are literally hundreds of people and perhaps two dozen threads on this subject on this forum alone. I also provided a link to website earlier that clearly showed images that illustrate the effect, apparently you "missed" them?
 Quoting: Anonymous Atrophysicist 1391715


Yes, apparently I did miss that link. Kindly provide the link again showing a "perfectly horizontal terminator on a rising moon".
Menow
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02/25/2013 06:51 PM
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You talk about an "angle on the terminator this time of year" as if the moon's orientation in the sky doesn't change from one hour to the next.
 Quoting: Menow 636186


At moonrise a very precise angle of the terminator should be easy to calculate at any given location and date. THIS IS IS PRESENTLY NOT THE CASE. As a person who has spent my whole 52 years observing nature, I know the patterns pretty well
 Quoting: Anonymous Atrophysicist 1391715


By the way... what is wrong with the calculations already presented, here, just a page or so back?
 Quoting: Menow 636186


It is impossible to get a horizontal terminator at moonrise any time of year south of the 60the latitude unless it is a lunar eclipse. It's basic math. 23 degrees of "tilt is the maximum possible deviation from vertical due to the tilt of the axis of the earth and the declination of the moons orbit from the ecliptic of 5 derees added to the latitude gives us the maximum angle from vertical the terminator can portend at moonrise.
 Quoting: Anonymous Atrophysicist 1391715


That is not responsive to my question. REPEAT: By the way... what is wrong with the calculations already presented, here, just a page or so back?
Menow
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02/25/2013 06:55 PM
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You talk about an "angle on the terminator this time of year" as if the moon's orientation in the sky doesn't change from one hour to the next.
 Quoting: Menow 636186


At moonrise a very precise angle of the terminator should be easy to calculate at any given location and date. THIS IS IS PRESENTLY NOT THE CASE. As a person who has spent my whole 52 years observing nature, I know the patterns pretty well
 Quoting: Anonymous Atrophysicist 1391715


By the way... what is wrong with the calculations already presented, here, just a page or so back?
 Quoting: Menow 636186


It is impossible to get a horizontal terminator at moonrise any time of year south of the 60the latitude unless it is a lunar eclipse. It's basic math. 23 degrees of "tilt is the maximum possible deviation from vertical due to the tilt of the axis of the earth and the declination of the moons orbit from the ecliptic of 5 derees added to the latitude gives us the maximum angle from vertical the terminator can portend at moonrise.
 Quoting: Anonymous Atrophysicist 1391715


So, why don't you show that this allegedly "impossible" event actually took place?

You have now given three different "maximum tilt" figures: 42 degrees, 22 degrees and 23 degrees. Which is it?
Menow
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02/25/2013 06:58 PM
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Arguing with stupid idiot is the folly of fools, you cannot win.
 Quoting: Anonymous Atrophysicist 1391715


That's your best excuse for not providing photo evidence showing what you claim has happened "dozens of times"?
Dr. AstroModerator
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02/25/2013 07:11 PM

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You talk about an "angle on the terminator this time of year" as if the moon's orientation in the sky doesn't change from one hour to the next.
 Quoting: Menow 636186


At moonrise a very precise angle of the terminator should be easy to calculate at any given location and date. THIS IS IS PRESENTLY NOT THE CASE. As a person who has spent my whole 52 years observing nature, I know the patterns pretty well
 Quoting: Anonymous Atrophysicist 1391715


By the way... what is wrong with the calculations already presented, here, just a page or so back?
 Quoting: Menow 636186


It is impossible to get a horizontal terminator at moonrise any time of year south of the 60the latitude unless it is a lunar eclipse. It's basic math.
 Quoting: Anonymous Atrophysicist 1391715


False. Basic math indeed:

Given that the apparent equatorial coordinates of the center point of the moon for 1/31/1971 at 2:45 UT were RA: 0h 19m 56.15s Dec: 6d 6' 0.83" (precessed to that date) and given that the moon is approximately half a degree wide in the sky, what were the approximate equatorial coordinates of the northern-most point of the moon on the equatorial grid at that time? Now, that was the easy part. The more challenging question is this, but if you're really better than I am this should not pose a problem for you; what is the apparent azimuth that corresponds to the above coordinates for the center point AND the northernmost point at the above time for the location 28.6084N 80.6043W? What is the difference in those two azimuth angles? At this point you should be starting to see with some degree of horror just how incredibly wrong you are. But to find the exact angle of the moon's terminator relative to the horizon you need to do lots more. For one thing, you need to calculate the position-angle of the moon's bright limb, but for now let's see how you get along with the answers to the above questions...

Last Edited by Dr. Astro on 02/25/2013 07:16 PM
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02/25/2013 07:34 PM
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...


At moonrise a very precise angle of the terminator should be easy to calculate at any given location and date. THIS IS IS PRESENTLY NOT THE CASE. As a person who has spent my whole 52 years observing nature, I know the patterns pretty well
 Quoting: Anonymous Atrophysicist 1391715


By the way... what is wrong with the calculations already presented, here, just a page or so back?
 Quoting: Menow 636186


It is impossible to get a horizontal terminator at moonrise any time of year south of the 60the latitude unless it is a lunar eclipse. It's basic math.
 Quoting: Anonymous Atrophysicist 1391715


False. Basic math indeed:

Given that the apparent equatorial coordinates of the center point of the moon for 1/31/1971 at 2:45 UT were RA: 0h 19m 56.15s Dec: 6d 6' 0.83" (precessed to that date) and given that the moon is approximately half a degree wide in the sky, what were the approximate equatorial coordinates of the northern-most point of the moon on the equatorial grid at that time? Now, that was the easy part. The more challenging question is this, but if you're really better than I am this should not pose a problem for you; what is the apparent azimuth that corresponds to the above coordinates for the center point AND the northernmost point at the above time for the location 28.6084N 80.6043W? What is the difference in those two azimuth angles? At this point you should be starting to see with some degree of horror just how incredibly wrong you are. But to find the exact angle of the moon's terminator relative to the horizon you need to do lots more. For one thing, you need to calculate the position-angle of the moon's bright limb, but for now let's see how you get along with the answers to the above questions...
 Quoting: Dr. Astro

There is absolutely no complex calculations or need to over complicate this issue. True genius explains in the simplest terms , not complicates to appear intelligent..True genius has no need to pretend.
I showed you precisely in very simple terms why the observations that have been seen all around the world are not possible at the latitudes they are occurring unless the moons orbit has changed. BY using terms like azimuth and "position-angle" of the moons limb, you prove to everyone you are not a genius nor even above average intelligence, but a copy paste parrot.
Anonymous Atrophysicist
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02/25/2013 07:38 PM
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Arguing with stupid idiot is the folly of fools, you cannot win.
 Quoting: Anonymous Atrophysicist 1391715


That's your best excuse for not providing photo evidence showing what you claim has happened "dozens of times"?
 Quoting: Menow 636186


It has not happened dozens of times, it is occurring on regular basis. It will happen again tonight.

The explanation I set forth is the only possible explanation since the moon is still rising in the East and setting in the west. If the moons orbit of the Earth were to become aligned with the ecliptic, lunar eclipses at moonrise would be very common, and they are, and that is why as the night wears on the moon returns to normal.
Anonymous Atrophysicist
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02/25/2013 07:41 PM
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razamanaz
 Quoting: Dr. Astro


By the way, how is that GLP observatory coming, genius astronomer? I heard you fucked up them telescopes so bad the manufacturers refused to honor the warranties, and yes I have my sources.

cruise
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...


By the way... what is wrong with the calculations already presented, here, just a page or so back?
 Quoting: Menow 636186


It is impossible to get a horizontal terminator at moonrise any time of year south of the 60the latitude unless it is a lunar eclipse. It's basic math.
 Quoting: Anonymous Atrophysicist 1391715


False. Basic math indeed:

Given that the apparent equatorial coordinates of the center point of the moon for 1/31/1971 at 2:45 UT were RA: 0h 19m 56.15s Dec: 6d 6' 0.83" (precessed to that date) and given that the moon is approximately half a degree wide in the sky, what were the approximate equatorial coordinates of the northern-most point of the moon on the equatorial grid at that time? Now, that was the easy part. The more challenging question is this, but if you're really better than I am this should not pose a problem for you; what is the apparent azimuth that corresponds to the above coordinates for the center point AND the northernmost point at the above time for the location 28.6084N 80.6043W? What is the difference in those two azimuth angles? At this point you should be starting to see with some degree of horror just how incredibly wrong you are. But to find the exact angle of the moon's terminator relative to the horizon you need to do lots more. For one thing, you need to calculate the position-angle of the moon's bright limb, but for now let's see how you get along with the answers to the above questions...
 Quoting: Dr. Astro

There is absolutely no complex calculations or need to over complicate this issue.
 Quoting: Anonymous Atrophysicist 1391715

LOL, he can't do it. I'll start you off with the first precursor question; the moon's northernmost point on the equatorial grid would approximately have the coordinates RA: 0h 19m 56.15s Dec: 6d 36' 0.83". It's a simple question, what are the azimuth angles, what is the difference in those angles? Answer the question.
BY using terms like azimuth and "position-angle" of the moons limb, you prove to everyone you are not a genius nor even above average intelligence, but a copy paste parrot.
 Quoting: IDW

No, what it means is I am familiar with the real terminology involved in doing the real calculations because I've actually done them. You are incapable of even answering the simple questions above. I haven't even begun to get complicated with you, you clearly couldn't handle it. The real calculations show that it is completely normal and my simple example above illustrates why.
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razamanaz
 Quoting: Dr. Astro


By the way, how is that GLP observatory coming, genius astronomer? I heard you fucked up them telescopes so bad the manufacturers refused to honor the warranties, and yes I have my sources.

cruise
 Quoting: Anonymous Atrophysicist 1391715


I did not fuck anything up. I aligned them properly, twice. They are currently working on the software, that is not my department. Post your "sources." You won't and can't because you're a pathetic liar who is lashing out now that he's been exposed.
astrobanner2
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No, what it means is I am familiar with the real terminology involved in doing the real calculations because I've actually done them.
 Quoting: Dr. Astro


Then perhaps you can explain why I have no problem setting up a telescope and having it actually work as it is supposed to and you can't do it?
cruise
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I did not fuck anything up. I aligned them properly, twice.
 Quoting: Dr. Astro


cruise

HMMM HMMM. Why would you have need you allign them twice if you got it right the first time, and both times were properly done and they still don't work?

You are a fucking idiot.

Fuck off my thread and start your own, you're stinking it up
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No, what it means is I am familiar with the real terminology involved in doing the real calculations because I've actually done them.
 Quoting: Dr. Astro


Then perhaps you can explain why I have no problem setting up a telescope and having it actually work as it is supposed to and you can't do it?
cruise
 Quoting: Anonymous Atrophysicist 1391715


Yes, I can.
Thread: **Breaking** FIRST UFO on GLP Observatory!! Comet/Object Flying Through Space!!
More pictures I took from the GLP observatory:
crabnebulaglpflamenebulaglpwidehorseglpnarrowhorseglp
Again, it works, it has been used by the members here, what they are currently working on with it has nothing to do with me. You have now been exposed not only as someone who can't do the simple calculations outlined above, but flat out lies when cornered.
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I did not fuck anything up. I aligned them properly, twice.
 Quoting: Dr. Astro


cruise

HMMM HMMM. Why would you have need you allign them twice if you got it right the first time, and both times were properly done and they still don't work?
 Quoting: Anonymous Atrophysicist 1391715

The Meade MAX Mount was having firmware and mechanical problems when I arrived. We aligned it, but it had to be shipped back to the factory for an overhaul. The first versions of that scope went through a quiet recall handled with everyone who purchased one very early on, but that one slipped through the cracks as it was sitting in a dealer's warehouse. It was aligned properly both times, however.
You are a fucking idiot.

Fuck off my thread and start your own, you're stinking it up
 Quoting: IDW

Awww, look how threatened poor widdle IDW feels. How cute!
astrobanner2
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I must admit I take a somewhat sadistic pleasure in torturing .gov shills.

I guess in that respect they have succeeded in reducing me to tier level of spiritual development at times. I suppose that is the intent. I shall endeavor not to let that happen again.
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...


It is impossible to get a horizontal terminator at moonrise any time of year south of the 60the latitude unless it is a lunar eclipse. It's basic math.
 Quoting: Anonymous Atrophysicist 1391715


False. Basic math indeed:

Given that the apparent equatorial coordinates of the center point of the moon for 1/31/1971 at 2:45 UT were RA: 0h 19m 56.15s Dec: 6d 6' 0.83" (precessed to that date) and given that the moon is approximately half a degree wide in the sky, what were the approximate equatorial coordinates of the northern-most point of the moon on the equatorial grid at that time? Now, that was the easy part. The more challenging question is this, but if you're really better than I am this should not pose a problem for you; what is the apparent azimuth that corresponds to the above coordinates for the center point AND the northernmost point at the above time for the location 28.6084N 80.6043W? What is the difference in those two azimuth angles? At this point you should be starting to see with some degree of horror just how incredibly wrong you are. But to find the exact angle of the moon's terminator relative to the horizon you need to do lots more. For one thing, you need to calculate the position-angle of the moon's bright limb, but for now let's see how you get along with the answers to the above questions...
 Quoting: Dr. Astro

There is absolutely no complex calculations or need to over complicate this issue.
 Quoting: Anonymous Atrophysicist 1391715

LOL, he can't do it. I'll start you off with the first precursor question; the moon's northernmost point on the equatorial grid would approximately have the coordinates RA: 0h 19m 56.15s Dec: 6d 36' 0.83". It's a simple question, what are the azimuth angles, what is the difference in those angles? Answer the question.
BY using terms like azimuth and "position-angle" of the moons limb, you prove to everyone you are not a genius nor even above average intelligence, but a copy paste parrot.
 Quoting: IDW

No, what it means is I am familiar with the real terminology involved in doing the real calculations because I've actually done them. You are incapable of even answering the simple questions above. I haven't even begun to get complicated with you, you clearly couldn't handle it. The real calculations show that it is completely normal and my simple example above illustrates why.
 Quoting: Dr. Astro


Notice how IDW is avoiding these calculations like the plague. There is a reason for that, a reason illuminated by my spreadsheet presented above.
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Yes, I can.
Thread: **Breaking** FIRST UFO on GLP Observatory!! Comet/Object Flying Through Space!!
More pictures I took from the GLP observatory:
:crabnebulaglp::flamenebulaglp::widehorseglp::narrowhorseglp:​
Again, it works, it has been used by the members here, what they are currently working on with it has nothing to do with me. You have now been exposed not only as someone who can't do the simple calculations outlined above, but flat out lies when cornered.
 Quoting: Dr. Astro


Prove those photos came from the GLP telescope. I happen to know it has NEVER worked
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I did not fuck anything up. I aligned them properly, twice.
 Quoting: Dr. Astro


cruise

HMMM HMMM. Why would you have need you allign them twice if you got it right the first time, and both times were properly done and they still don't work?

You are a fucking idiot.

Fuck off my thread and start your own, you're stinking it up
 Quoting: Anonymous Atrophysicist 1391715
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Yes, I can.
Thread: **Breaking** FIRST UFO on GLP Observatory!! Comet/Object Flying Through Space!!
More pictures I took from the GLP observatory:
crabnebulaglpflamenebulaglpwidehorseglpnarrowhorseglp
Again, it works, it has been used by the members here, what they are currently working on with it has nothing to do with me. You have now been exposed not only as someone who can't do the simple calculations outlined above, but flat out lies when cornered.
 Quoting: Dr. Astro


Prove those photos came from the GLP telescope. I happen to know it has NEVER worked
 Quoting: Anonymous Atrophysicist 1391715


You are such a liar! The proof is right there!
Thread: **Breaking** FIRST UFO on GLP Observatory!! Comet/Object Flying Through Space!!
People all saw the scope in action. The videos from the live webcasts are all still right here:
[link to www.justin.tv]
astrobanner2
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LOL, he can't do it. I'll start you off with the first precursor question; the moon's northernmost point on the equatorial grid would approximately have the coordinates RA: 0h 19m 56.15s Dec: 6d 36' 0.83". It's a simple question, what are the azimuth angles, what is the difference in those angles? Answer the question.
 Quoting: Dr. Astro


Come on IDW, stop avoiding it and answer the question.
astrobanner2
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02/25/2013 08:13 PM
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LOL, he can't do it. I'll start you off with the first precursor question; the moon's northernmost point on the equatorial grid would approximately have the coordinates RA: 0h 19m 56.15s Dec: 6d 36' 0.83". It's a simple question, what are the azimuth angles, what is the difference in those angles? Answer the question.
 Quoting: Dr. Astro


Come on IDW, stop avoiding it and answer the question.
 Quoting: Dr. Astro


I'm not Trained poodle, i don't jump through hoops for an idiot> I showed the only proof necessary To prove you a pretender and an idiot and that i was right about the moon and YOU, and that is why I had to reset my ip to post again
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Arguing with stupid idiot is the folly of fools, you cannot win.
 Quoting: Anonymous Atrophysicist 1391715


That's your best excuse for not providing photo evidence showing what you claim has happened "dozens of times"?
 Quoting: Menow 636186


It has not happened dozens of times, it is occurring on regular basis. It will happen again tonight.

The explanation I set forth is the only possible explanation since the moon is still rising in the East and setting in the west. If the moons orbit of the Earth were to become aligned with the ecliptic, lunar eclipses at moonrise would be very common, and they are, and that is why as the night wears on the moon returns to normal.
 Quoting: Anonymous Atrophysicist 1391715


For someone that keeps asking for photographic dated proof where is yours? Where are the pictures?...................yup thought so no where to be found.**adds Anonymous Atrophysicist to the lying attention seeking imbecile list**
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No, what it means is I am familiar with the real terminology involved in doing the real calculations because I've actually done them.
 Quoting: Dr. Astro


Then perhaps you can explain why I have no problem setting up a telescope and having it actually work as it is supposed to and you can't do it?
cruise
 Quoting: Anonymous Atrophysicist 1391715


If you have no problem setting up and using the scope, then you have already proved the Moon is moving as predicted. If your telescope can track it, it is moving in no unpredictable way at all. QED.

Thanks for proving Astro's case (more than he already had!).
Anonymous Coward
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02/25/2013 08:38 PM
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Re: WARNING: SOLAR DATA PAGE COMPLETELY CENSORED,DATA ON OTHER SOURCES BEING FABRICATED!
Yes, I can.
Thread: **Breaking** FIRST UFO on GLP Observatory!! Comet/Object Flying Through Space!!
More pictures I took from the GLP observatory:
:crabnebulaglp::flamenebulaglp::widehorseglp::narrowhorseglp:​
Again, it works, it has been used by the members here, what they are currently working on with it has nothing to do with me. You have now been exposed not only as someone who can't do the simple calculations outlined above, but flat out lies when cornered.
 Quoting: Dr. Astro


Prove those photos came from the GLP telescope. I happen to know it has NEVER worked
 Quoting: Anonymous Atrophysicist 1391715


You are either a real total fucking idiot or you know damn well what you are doing, that is, starting arguments by calling others shills to keep from posting proof.

The GLP telescope controls have been posted on here AND used by GLP posters.


You obviously don't know a damn thing on Astronomy, I can tell that and I've only read several posts of yours on here.

Astrophysicist my arse !
#Geomagnetic_Storm#
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02/25/2013 08:45 PM

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Re: WARNING: SOLAR DATA PAGE COMPLETELY CENSORED,DATA ON OTHER SOURCES BEING FABRICATED!
Yes, I can.
Thread: **Breaking** FIRST UFO on GLP Observatory!! Comet/Object Flying Through Space!!
More pictures I took from the GLP observatory:
crabnebulaglpflamenebulaglpwidehorseglpnarrowhorseglp
Again, it works, it has been used by the members here, what they are currently working on with it has nothing to do with me. You have now been exposed not only as someone who can't do the simple calculations outlined above, but flat out lies when cornered.
 Quoting: Dr. Astro


Prove those photos came from the GLP telescope. I happen to know it has NEVER worked
 Quoting: Anonymous Atrophysicist 1391715


It has worked for a while idiot... I was watching people using it here.
Dr. AstroModerator
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02/25/2013 08:47 PM

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Re: WARNING: SOLAR DATA PAGE COMPLETELY CENSORED,DATA ON OTHER SOURCES BEING FABRICATED!
I'm not Trained poodle, i don't jump through hoops for an idiot> I showed the only proof necessary To prove you a pretender and an idiot and that i was right about the moon and YOU, and that is why I had to reset my ip to post again
 Quoting: Anonymous Atrophysicist 1384202


You won't answer the question because you can't. If you did you would see that the difference in azimuth was nearly as much as the total added to the declination. Meaning the moon was nearly horizontal at that point. Now let's move on to figure out the exact angle of the moon relative to the horizon. What was the position-angle of the moon's bright limb at that time? Hint: you'll need to figure out where the sun was at the same time.
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02/25/2013 09:10 PM
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Re: WARNING: SOLAR DATA PAGE COMPLETELY CENSORED,DATA ON OTHER SOURCES BEING FABRICATED!
Arguing with stupid idiot is the folly of fools, you cannot win.
 Quoting: Anonymous Atrophysicist 1391715


That's your best excuse for not providing photo evidence showing what you claim has happened "dozens of times"?
 Quoting: Menow 636186


It has not happened dozens of times, it is occurring on regular basis. It will happen again tonight.
 Quoting: Anonymous Atrophysicist 1391715


Sorry? What will happen tonight? You have been claiming that the moon has risen with a "perfectly horizontal terminator". You are claiming that will happen again tonight? OK- then it should be no problem for you to take an image showing that, right?

The explanation I set forth is the only possible explanation since the moon is still rising in the East and setting in the west. If the moons orbit of the Earth were to become aligned with the ecliptic, lunar eclipses at moonrise would be very common, and they are, and that is why as the night wears on the moon returns to normal.
 Quoting: Anonymous Atrophysicist 1391715


Sorry? Explanation for what? I'm still waiting for you to show evidence for the alleged event you want explained.

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