UNKNOWN OBJECT HEADING THIS WAY!!! UPDATE DEC8 2012!!! OH SHIT!!!

Why is this pinned

Which one was the first one? There's so many! I've posted comments on the ones I've found talking about this, I just posted a comment on the OP's video as a matter of fact.

Malarkey! GLP has become






Malarkey

Because people find it interesting...............and because it ties in with the 2012 meme..........going on right now.

What's interesting about it. The fact that ACs with no knowledge on space and a big imagination think something is up when someone like Dr. Astro who clear has a lot of knowledge on space has brought this to light.

My lottery ticked failed again, yes Unknown Object please come destroy the earth now.

Astro also uses gubment websites for his rebuttle.

Good hunch, thats what suspicious 0bserver said

Old news. its going to make a close approach, date is February 15th i believe. however in 2045-2060 it will approach within .09 earth radii which equates to about...200 miles from the surface. its too small to leave more then a bunch of small craters, no issue. its all on the JPL table. id be more concerned if it somehow changes course drastically.

[link to www.minorplanetcenter.net]
2012 11 29.39934 19 16 21.76 -29 16 55.3 11.5 T E27 – Thornlands MPEC X02
2012 11 29.42881 19 16 20.04 -29 15 26.2 11.6 T E27 – Thornlands MPEC X02
2012 11 30.38652 19 15 28.09 -28 29 57.2 11.6 T E27 – Thornlands MPEC X02
2012 11 30.38694 19 15 28.07 -28 29 56.3 11.5 T E27 – Thornlands MPEC X02
2012 11 30.39175 19 15 27.83 -28 29 41.8 11.8 T E27 – Thornlands MPEC X02
2012 11 30.40102 19 15 27.28 -28 29 16.2 11.6 T E27 – Thornlands MPEC X02
2012 11 30.41491 19 15 26.56 -28 28 36.5 11.7 T E27 – Thornlands MPEC X02
2012 11 30.41944 19 15 26.33 -28 28 24.3 11.7 T E27 – Thornlands MPEC X02
Thornlands - that's AMATEUR astronomer Terry Lovejoy's (yes, Lovejoy as in comet Lovejoy) observatory.
2012 12 03.03368 19 13 10.45 -26 29 42.5 H06 – iTelescope Observatory, Mayhill MPEC X14
2012 12 03.03458 19 13 10.43 -26 29 39.8 H06 – iTelescope Observatory, Mayhill MPEC X14
2012 12 03.03548 19 13 10.36 -26 29 37.7 H06 – iTelescope Observatory, Mayhill MPEC X14
2012 12 03.03638 19 13 10.29 -26 29 35.5 H06 – iTelescope Observatory, Mayhill MPEC X14
2012 12 03.03731 19 13 10.25 -26 29 32.8 H06 – iTelescope Observatory, Mayhill MPEC X14
2012 12 03.03821 19 13 10.20 -26 29 30.5 10.5 T H06 – iTelescope Observatory, Mayhill MPEC X1
iTelescope, rentable online telescopes used by amateurs.
2012 12 01.00076 19 14 55.40 -28 01 26.5 13.8 T H47 – Vicksburg MPEC X02
2012 12 01.00172 19 14 55.36 -28 01 23.1 13.9 T H47 – Vicksburg MPEC X02
2012 12 01.00267 19 14 55.33 -28 01 21.2 13.7 T H47 – Vicksburg MPEC X02
2012 12 01.00517 19 14 55.19 -28 01 14.0 13.6 T H47 – Vicksburg MPEC X02
Vicksburg, the private observatory of amateur astronomer Charles Bell.
[link to sites.google.com (secure)]
Hey, look at that, he uses an LX200 just like me. These data were used to help calculate the orbit of C/2012 V4, from which I can and did directly determine what STEREO-B HI2 saw matches C/2012 V4 exactly.

Might be so but it's better then anything the opposing side brings to the table.

True. The thing is, if you are of a conspiracy mind, government sites may lie.

Yeah, I have deja vu...this was already discussed and dissected to death and finally verified as a doom-DUD.

Except that the current trajectory is traveling in a way that does not coincide with jpl. Plus it seems as though the object in said video will arrive sooner than projected Feb. date.

I rewatched your rebuttal video.......awesome graphics, BTW------are you saying the "distortion" you talk of is the reason the comet is coming at a steep angle?

And is Swan supposed to be coming in at that steep angle.

Its current trajectory coincides perfectly with the orbit JPL has for it, which was derived directly from these data. JPL's java applet is not an appropriate tool for trying to match up with what STEREO Behind sees, Celestia, however, is one such tool.

huh, actually, now that i AM looking at the Data table.....this seems like it is moving a bit to slow to be natural....i mean, look at the calculated approaches from the past that have been extrapolated from its orbit.

FUTURE CLOSE APPROACHES (note measurement is Earth Radii not AU. as in fractions of the width of our planet NOT its orbit.): [link to neo.jpl.nasa.gov]

its been staying VERY close to earth. and keeps coming really close.

(past approaches) : [link to ssd.jpl.nasa.gov]

No, actually the 136.39480 degree inclination is why it is coming in at a steep angle to the ecliptic.

Actually, the AC WAS right. It is not the object everybody thought it was. It was Swan Comet.

And notice the original poster's video did not mention it hitting the earth. Only that it may pass close to earth. At a steep angle. People were acting like it would hit the earth.

I just don't buy that it IS C/2012 V4. I watched the videos. I'm no expert but I don't see a smoking gun.

What are you talking about? This isn't 2012 DA14.

It occupies the same physical space as C/2012 V4. You can think whatever you like of course, but I'm telling you, there's nothing about this that indicates it's anything but the comet and its trajectory through HI2 is an exact match. That means it has the same orbit and is right where C/2012 V4 should be.

I still stand behind my original point as to why this is pinned. This was heavily discussed last night. There is no threat so i don't see the point in a comet thread being pinned when were heading into a shower anyways.

I'm an English major, Dr. Astro----------complex math and astronomical terms are beyond me (Sorry. And be patient, please)------------------

The inclination you speak of----is that in relation to the camera/camera angle?

Or just the way it moves through the sky?

Explain it in layman's terms, please, for a "novice."

Its definitly not a commet, MAss is to high. more likely iron
Calculated density given Radius of .045 KM and mass of 1.3+e08 is
~34 kg per cubic meter

THE FUCK IS THIS THING
water, and water ice is only 1kg cubic meter

It's the inclination to the earth's orbital plane, the ecliptic. Wikipedia has a pretty good diagram of it:
[link to en.wikipedia.org]

It's interesting that those who are of a conspiracy mind refuse to believe government sources, but they'll believe almost anything anybody else says with little-to-no evidence.

LOL, where did you get these numbers? Oh wait, I see now, you got them from here:
[link to neo.jpl.nasa.gov]
AGAIN, this is NOT 2012 D14. 2012 DA14 is an asteroid, not a comet. It has nothing to do with C/2012 V4, it is not what you see in this video.

The following is a Copy paste from JPL: links @
[link to ssd.jpl.nasa.gov]
[link to neo.jpl.nasa.gov]
TL;DR Close approach on Febuary 15th 2013, and VERY CLOSE aproach *under space station orbit* on 2054 possible impact.

Close approach Data for 2012 DA14
2013-Feb-15 19:25 GMT

Time uncertainty (D_HH:MM)
0_00:02

Body
Earth

Nominal Distance (AU. This is the most likely, and in center of probability calculation)
0.000233799507126153 AU : ~ 21 733.0219 miles

Minimum Distance (AU. inside of probability calculations
0.000181313271702344 AU : ~ 16 854.1215 Miles


Max Distance (AU. Outside of probability calculations)
0.000353865810509171 AU : ~ 32 893.8821 Miles

Velocity Relitive to Earth (KM/S)
7.78009878225669 KM/S

OBJECT PARAMETERS

size
0.045 km

Velocity (if impact)
12.72 km/s

Inclination
10.33692828105874 Deg

Palermo Scale (max. positive = bad)
-3.67

Impact Probability
0.033000000% chance of Earth impact

Number of future close approaches computed
36

FUTURE CALCULATIONS (top 3)
DATE (y-m-d) Distance in Earth Radius Torino scale
2033-02-15 0.08 (512 km from surface) 0
2053-02-15 0.06 (384 km from surface) 0
2054-02-15 0.02 (128 km from surface) 0


Analysis based on
188 observations spanning 79.384 days
(2012-Feb-23.03431 to 2012-May-12.41842)


IMPACT CALCULATION
*assuming dense rock, water impact Depth 500 meters. second calculation is land impact*

Water impact
The projectile begins to breakup at an altitude of 49400 meters = 162000 ft
The projectile bursts into a cloud of fragments at an altitude of 27400 meters = 89700 ft
The residual velocity of the projectile fragments after the burst is 9.13 km/s = 5.67 miles/s
The energy of the airburst is 5.62 x 1015 Joules = 1.34 x 100 MegaTons.
No crater is formed, although large fragments may strike the surface.


Airblast felt at 100 km
1.62 mph @ 50 dB

Tsunami
36.6 cm (foot and 2 inches)

land impact

The projectile begins to breakup at an altitude of 49400 meters = 162000 ft
The projectile bursts into a cloud of fragments at an altitude of 27400 meters = 89700 ft
The residual velocity of the projectile fragments after the burst is 9.13 km/s = 5.67 miles/s
The energy of the airburst is 5.62 x 1015 Joules = 1.34 x 100 MegaTons.
No crater is formed, although large fragments may strike the surface.

Airblast felt at 100 km
1.62 mph @ 50 dB


*parameters uped for nickel iron asteroid*

Water impact (500 m depth)

The projectile begins to breakup at an altitude of 8590 meters = 28200 ft
The projectile bursts into a cloud of fragments at an altitude of 3460 meters = 11300 ft
The residual velocity of the projectile fragments after the burst is 4.2 km/s = 2.61 miles/s
The energy of the airburst is 2.75 x 1016 Joules = 6.57 x 100 MegaTons.
Large fragments strike the surface and may create a crater strewn field.

Airblast @ 100km
8.34 mph @ 64 dB

Tsunami
35.6 cm (foot and 2 inches)

Land impact

The projectile begins to breakup at an altitude of 8590 meters = 28200 ft
The projectile bursts into a cloud of fragments at an altitude of 3460 meters = 11300 ft
The residual velocity of the projectile fragments after the burst is 4.2 km/s = 2.61 miles/s
The energy of the airburst is 2.75 x 1016 Joules = 6.57 x 100 MegaTons.
Large fragments strike the surface and may create a crater strewn field.

Airblast @ 100km
8.34 mph @ 64 dB

Are comets usually coming in from below the ecliptic?
Furthermore, isn't it moving away from the sun?