How To Solve This Equation? 3/1(1+2) = x

This ^^

Thanks Clam, I was actually going to write up a long boring paragraph explaining this, but this video explains it much better than I ever could. Great find!

Copy paste this into Google.

((0^0^0)^(0^0^0)+(0^0^0)^(0^0^0)+(0^0^0)^(0^0^0)+(0^0^0)^(0^​0^0))(((0^0)/((0^0^0)^(0^0^0)+(0^0^0)^(0^0^0)))!)^((0^0^0)^(0​^0^0)+(0^0^0)^(0^0^0))

Multiplicative Identity:

1a = a

[link to mathworld.wolfram.com]

[link to www.cartage.org.lb]

Any coefficient 1, is redundant. therefore,

3/1(1+2) = 3/(1+2), since 1 is the coefficient of (2+1)

Ans: 1

Easy.

I cant believe that after this much debate anyone could say 1 when the answer is 9

1. Calculations must be done from left to right.

2. Calculations in brackets (parenthesis) are done first. When you have more than one set of brackets, do the inner brackets first.

3. Exponents (or radicals) must be done next.

4. Multiply and divide in the order the operations occur.

5. Add and subtract in the order the operations occur.

X=9

I bet you ignored the references. No wonder you get 9. You have no idea how to do the problem.

How to solve this problem:

Figure out what the terms are. Simplify if possible, and apply an principles or laws to make the solve process easier. Apply order of operations. Solve.

1a, 1(x+y), 1pi;

Anything with a coefficient of 1, the one doesn't need to be written. Anything without a 1, the 1 CAN be written, but usually is not. However, it is ALWAYS there regardless if it is written or not.

THEREFORE:
a, (x+y), and pi; ALL have a coefficient of 1.
a = 1a
(x+y) = 1(x+y)
pi; = 1pi;

ALSO: 1(1+2) = (1+2). Lose the one, and solve, since you have no idea how grouping works.

3/1(1+2) is the same as 3/(1+2)

ANS: 1

This will never change, unless the identity law of multiplication changes where 1*a != a.

"9er" snarky comments of
-It is 9 you morons
-How is this still going on after 140 million pages? It is still 9!
-You are wrong, it is 9

All those comments are useless redirects since you are too lazy to read any of the references posted. the answer is ONE. It will remain ONE. You can say it is whatever you want, just like on a test. However, like an exam, you will get it wrong. Say it 9, 5, 113, I don't care. This isn't a majority vote. But, there is a good analogy:



Last Edited by caper_26 on 01/23/2013 01:47 PM

the answer is 9

After hours of calculating on my super computer I can honestly say that

3/1(1+2) does = x

then why do you keep posting about it over and over and over and over again?

1(1+2).......3
______ * _____ = x * 1(1+2)
...1........1(1+2)


9
__ = x * 3

3


3 = x * 3


3
__ = x

3


1 = x

Last Edited by Bent on 01/23/2013 04:49 PM

So that when someone else comes here to read about it, they don't get poisoned by the stupidity that comes before them

so you do care

Here is how to rewrite the problem properly when the obelus is used. Notice how they don't change 2x into 2 * x and then use only the 2 for the divisor??

[link to i47.tinypic.com]

ref: [link to go.hrw.com]

The 9ers somewhat understand the order of operations, but it is the algebra that is killing them in the end

Reaganomics = 9
Obama whatever he calls it = 1

Maths says it is ONE. Simpletons say it is 9, which is understandable.