## Only for geniuses! | |

Anonymous Coward User ID: 27582823 France 11/15/2013 10:26 PM Report Abusive Post Report Copyright Violation | |

Anonymous Coward User ID: 49969317 United States 11/15/2013 10:27 PM Report Abusive Post Report Copyright Violation | jesus christ. this really is not very hard. 2=6 3=12 4=20 5=30 6=42 7=56 8=72 9=90 1=2 the difference between the answer of one problem and the answer of the next is equal to double the first number. 12-6=3*2 20-12=4*2 90-72=9*2 or the first number multiplied by the first number of the next problem equals the solution of the first problem. 3*2=6 4*3=12 5*4=20 10*9=90 simple. |

Anonymous Coward User ID: 49953507 United States 11/15/2013 10:27 PM Report Abusive Post Report Copyright Violation | |

Anonymous Coward User ID: 4396096 United States 11/15/2013 10:29 PM Report Abusive Post Report Copyright Violation | |

ProNerdUser ID: 13856469 United States 11/15/2013 10:32 PM Report Abusive Post Report Copyright Violation | Yours is the 3rd correct answer in the thread : 2*3 3*4 4*5 5*6 6*7 7*8 8*9 9*0 Actualisation: If f(2)=12, f(3)=12, f(4)=20, f(5)=30, f(6)=42, define f(n) a) f(n)=n*(n+1) so f(9)=9*10=90 b) with [n] = nth prime number, f(n)=[n]+[2n-2] so f(9)=[9]+[2*9-2]=23+[16]=23+53=76 c) f(n) = n * ((n+1) modulo 10)) so f(9) = 9 * (10 modulo 10) = 9 * 0 = 0 As I said, my kind of girl... Anonymous Coward 27582823 This breaks down if you keep going. ProNerd Yours is the 3rd correct answer in the thread : 2*3 3*4 4*5 5*6 6*7 7*8 8*9 9*0 Actualisation: If f(2)=12, f(3)=12, f(4)=20, f(5)=30, f(6)=42, define f(n) a) f(n)=n*(n+1) so f(9)=9*10=90 b) with [n] = nth prime number, f(n)=[n]+[2n-2] so f(9)=[9]+[2*9-2]=23+[16]=23+53=76 c) f(n) = n * ((n+1) modulo 10)) so f(9) = 9 * (10 modulo 10) = 9 * 0 = 0 As I said, my kind of girl... Anonymous Coward 27582823 This breaks down if you keep going. ProNerd If I not misunderstand your answer because my bad english you say it's wrong ? 2 * (3 modulo 10) = 6 3 * (4 modulo 10) = 12 4 * (5 modulo 10) = 20 5 * (6 modulo 10) = 30 6 * (7 modulo 10) = 42 This a match. and 9 * (10 modulo 10) = 0 Anonymous Coward 27582823 so... 2*3=6 3*4=12 4*5=20 5*6=30 6*7=42 7*8=56 8*9=72 9*0=0 10*-1=-10 11*-2=-22 12*-3=-36 or 2*3=6 3*4=12 4*5=20 5*6=30 6*7=42 7*8=56 8*9=72 9*0=0 0*-1=-0 -1*-2=2 -3*-3=9 I'm saying that if you continue your pattern it fails to plot a constant curve. an in.... IF: 2=6 3=12 6+6 4=20 12+8 5=30 20+10 6=42 30+12 7=56 42+14 8=72 56+16 9=90 72+18 10=110 90+20 11=132 110+22 12=156 132+24 13=182 156+26 or 2x3=6 3x4=12 4x5=20 5x6=30 6x7=42 7x8=56 8x9=64 9x10=90 10x11=110 11x12=132 12x13=156 13x14=182 these are the two simple patterns I see, both indicate 9=90 |

Anonymous Coward User ID: 27582823 France 11/15/2013 10:33 PM Report Abusive Post Report Copyright Violation | If f(2)=12, f(3)=12, f(4)=20, f(5)=30, f(6)=42, define f(n) and give f(9) a) f(n)=n*(n+1) so f(9)=9*10=90 b) with [n] = nth prime number, f(n)=[n]+[2n-2] so f(9)=[9]+[2*9-2]=23+[16]=23+53=76 c) f(n) = n * ((n+1) modulo 10)) so f(9) = 9 * (10 modulo 10) = 9 * 0 = 0 There is also a strange cabal which insist saying 72 is correct but failing to define f(n). |

Anonymous Coward User ID: 17260532 Canada 11/15/2013 10:34 PM Report Abusive Post Report Copyright Violation | |

Anonymous Coward (OP)User ID: 49763587 United States 11/15/2013 10:35 PM Report Abusive Post Report Copyright Violation | 72 and I didn't look at any of the other responses. Took me about 10 seconds to see pattern. Quoting: Squonk1960 Still waiting for any justification about 72... Anonymous Coward 27582823 Another Most people are responding this way: 2=6 3=12 4=20 5=30 6=42 7=56 8=72 9=90 But this is why I think it's 72: 3x2=6 4x3=12 5x4=20 6x5=30 7x6=42 8x7=56 9x8= 72!!!!!!!!! Anonymous Coward 49763587 Sorry to be there but you're cheating with your 1st post. 9=72 would be correct IF 3=6 4=12 5=20 6=30 7=42 As you asked : 2=6 3=12 4=20 5=30 6=42 We have 9=72 Anonymous Coward 27582823 Again 3x 2=64x 3=125x 4=206x 5=307x 6=428x 7=569x 8=72Not cheating... |

Anonymous Coward User ID: 34388912 United States 11/15/2013 10:36 PM Report Abusive Post Report Copyright Violation | I don't know if this has been posted before. There is a math problem (joke?) that has been stirring a debate. Originated on Facebook and driving some crazy lol. Quoting: Can any of you on here come to the solution for this pattern(Pi?AR?). And if this has been answered what is the correct one? Thanks! IF: 2=6 3=12 4=20 5=30 6=42 Then:9=?? Anonymous Coward 49763587 Too easy. 90 |

Anonymous Coward (OP)User ID: 49763587 United States 11/15/2013 10:37 PM Report Abusive Post Report Copyright Violation | |

Anonymous Coward User ID: 4396096 United States 11/15/2013 10:39 PM Report Abusive Post Report Copyright Violation | |

Anonymous Coward (OP)User ID: 49763587 United States 11/15/2013 10:39 PM Report Abusive Post Report Copyright Violation | |

Anonymous Coward User ID: 27582823 France 11/15/2013 10:42 PM Report Abusive Post Report Copyright Violation | ...Yours is the 3rd correct answer in the thread : 2*3 3*4 4*5 5*6 6*7 7*8 8*9 9*0 Actualisation: If f(2)=12, f(3)=12, f(4)=20, f(5)=30, f(6)=42, define f(n) a) f(n)=n*(n+1) so f(9)=9*10=90 b) with [n] = nth prime number, f(n)=[n]+[2n-2] so f(9)=[9]+[2*9-2]=23+[16]=23+53=76 c) f(n) = n * ((n+1) modulo 10)) so f(9) = 9 * (10 modulo 10) = 9 * 0 = 0 As I said, my kind of girl... Anonymous Coward 27582823 This breaks down if you keep going. ProNerd ...Yours is the 3rd correct answer in the thread : 2*3 3*4 4*5 5*6 6*7 7*8 8*9 9*0 Actualisation: If f(2)=12, f(3)=12, f(4)=20, f(5)=30, f(6)=42, define f(n) a) f(n)=n*(n+1) so f(9)=9*10=90 b) with [n] = nth prime number, f(n)=[n]+[2n-2] so f(9)=[9]+[2*9-2]=23+[16]=23+53=76 c) f(n) = n * ((n+1) modulo 10)) so f(9) = 9 * (10 modulo 10) = 9 * 0 = 0 As I said, my kind of girl... Anonymous Coward 27582823 This breaks down if you keep going. ProNerd If I not misunderstand your answer because my bad english you say it's wrong ? 2 * (3 modulo 10) = 6 3 * (4 modulo 10) = 12 4 * (5 modulo 10) = 20 5 * (6 modulo 10) = 30 6 * (7 modulo 10) = 42 This a match. and 9 * (10 modulo 10) = 0 Anonymous Coward 27582823 so... 2*3=6 3*4=12 4*5=20 5*6=30 6*7=42 7*8=56 8*9=72 9*0=0 10*-1=-10 11*-2=-22 12*-3=-36 or 2*3=6 3*4=12 4*5=20 5*6=30 6*7=42 7*8=56 8*9=72 9*0=0 0*-1=-0 -1*-2=2 -3*-3=9 I'm saying that if you continue your pattern it fails to plot a constant curve. an in.... IF: 2=6 3=12 6+6 4=20 12+8 5=30 20+10 6=42 30+12 7=56 42+14 8=72 56+16 9=90 72+18 10=110 90+20 11=132 110+22 12=156 132+24 13=182 156+26 or 2x3=6 3x4=12 4x5=20 5x6=30 6x7=42 7x8=56 8x9=64 9x10=90 10x11=110 11x12=132 12x13=156 13x14=182 these are the two simple patterns I see, both indicate 9=90 ProNerd 90 have been given from the start. You're wrong two times, 1) you say : 2*3=6 3*4=12 4*5=20 5*6=30 6*7=42 7*8=56 8*9=72 9*0=0 10*-1=-10 11*-2=-22 12*-3=-36 This is not my definition, it is : f(n)=n*((n+1) mod 10)), meaning : 2*3=6 3*4=12 4*5=20 5*6=30 6*7=42 7*8=56 8*9=72 9*0=0 10*1=10 11*2=22 12*3=36 And even if it was, the fact that the definition is verified for 2,3,4,5,6 validate the definition, wich is the question asked. Nobody asked the solution must be a constant curve or anything else, it have to verify 2->6 3->12 4->20 5->30 6->42 That's all |

Anonymous Coward User ID: 49996919 United States 11/15/2013 10:43 PM Report Abusive Post Report Copyright Violation | |

Anonymous Coward User ID: 27582823 France 11/15/2013 10:43 PM Report Abusive Post Report Copyright Violation | Another Most people are responding this way: 2=6 3=12 4=20 5=30 6=42 7=56 8=72 9=90 But this is why I think it's 72: 3x2=6 4x3=12 5x4=20 6x5=30 7x6=42 8x7=56 9x8= 72!!!!!!!!! Anonymous Coward 49763587 Sorry to be there but you're cheating with your 1st post. 9=72 would be correct IF 3=6 4=12 5=20 6=30 7=42 As you asked : 2=6 3=12 4=20 5=30 6=42 We have 9=72 Anonymous Coward 27582823 Again 3x 2=64x 3=125x 4=206x 5=307x 6=428x 7=569x 8=72Not cheating... Anonymous Coward 49763587 lol... look yourself your bold characters, 72 is for 8 here |

Anonymous Coward User ID: 49996919 United States 11/15/2013 10:44 PM Report Abusive Post Report Copyright Violation | |

ProNerdUser ID: 13856469 United States 11/15/2013 10:45 PM Report Abusive Post Report Copyright Violation | |

Anonymous Coward User ID: 17260532 Canada 11/15/2013 10:48 PM Report Abusive Post Report Copyright Violation | |

xtcssoUser ID: 49620053 Canada 11/15/2013 10:48 PM Report Abusive Post Report Copyright Violation | I don't know if this has been posted before. There is a math problem (joke?) that has been stirring a debate. Originated on Facebook and driving some crazy lol. Quoting: Can any of you on here come to the solution for this pattern(Pi?AR?). And if this has been answered what is the correct one? Thanks! IF: 2=6 3=12 4=20 5=30 6=42 Then:9=?? Anonymous Coward 49763587 2x3 3x4 4x5 5x6 6x7 7x8 8x9 9x10 90... xtcsso |

xtcssoUser ID: 49620053 Canada 11/15/2013 10:49 PM Report Abusive Post Report Copyright Violation | I don't know if this has been posted before. There is a math problem (joke?) that has been stirring a debate. Originated on Facebook and driving some crazy lol. Quoting: Can any of you on here come to the solution for this pattern(Pi?AR?). And if this has been answered what is the correct one? Thanks! IF: 2=6 3=12 4=20 5=30 6=42 Then:9=?? Anonymous Coward 49763587 2x3 3x4 4x5 5x6 6x7 7x8 8x9 9x10 90... xtcsso an yes like so many i reply before seeing all reply lol xtcsso |

Anonymous Coward User ID: 27582823 France 11/15/2013 10:49 PM Report Abusive Post Report Copyright Violation | |

Anonymous Coward (OP)User ID: 49763587 United States 11/15/2013 10:50 PM Report Abusive Post Report Copyright Violation | YES this is cheating, we are looking for 9 not 8, you have to keep going. We are starting with 2 not 3. :) 3x 2=64x 3=125x 4=206x 5=307x 6=428x 7=569x 8=7210x 9=90ProNerd These are not my equations simply providing how some are saying they get 72 I did post that it gave the sum for 8 not 9. If it were I doing it, I think I would leave the digits 7 and 8 out of it, that would be cheating as they are not given. |

Anonymous Coward User ID: 17260532 Canada 11/15/2013 10:51 PM Report Abusive Post Report Copyright Violation | Reminder for new page and new comers. Correct answers so far Quoting: If f(2)=12, f(3)=12, f(4)=20, f(5)=30, f(6)=42, define f(n) and give f(9) a) f(n)=n*(n+1) so f(9)=9*10=90 b) with [n] = nth prime number, f(n)=[n]+[2n-2] so f(9)=[9]+[2*9-2]=23+[16]=23+53=76 c) f(n) = n * ((n+1) modulo 10)) so f(9) = 9 * (10 modulo 10) = 9 * 0 = 0 There is also a strange cabal which insist saying 72 is correct but failing to define f(n). Anonymous Coward 27582823 you god damn french man doing things all long and drawn out and shit.. whats with all the algebraic non-sense.. couldn't you just see the pattern at a first glance or what? |

Anonymous Coward User ID: 4396096 United States 11/15/2013 10:52 PM Report Abusive Post Report Copyright Violation | 2=6 Quoting: 3=12 (12 is 6+6) 4=20 (20 is 12+8) 5=30 (30 is 20+10) 6=42 (42 is 30+12) 9=56 (56 is 42+14) Anonymous Coward 4396096 2=6 3=12 (12 is 6+6) 4=20 (20 is 12+8) 5=30 (30 is 20+10) 6=42 (42 is 30+12) 7=56 (56 is 42+14) 8=72 (72 is 56+16) 9=90 (90 is 72+18) you just forgot 7 & 8 Anonymous Coward 27582823 No, I did not forgot anything. |

Anonymous Coward User ID: 17260532 Canada 11/15/2013 10:52 PM Report Abusive Post Report Copyright Violation | |

g0ld3nb0yUser ID: 33039683 United States 11/15/2013 10:57 PM Report Abusive Post Report Copyright Violation | |

ProNerdUser ID: 13856469 United States 11/15/2013 11:04 PM Report Abusive Post Report Copyright Violation | 90 have been given from the start. Quoting: You're wrong two times, 1) you say : 2*3=6 3*4=12 4*5=20 5*6=30 6*7=42 7*8=56 8*9=72 9*0=0 10*-1=-10 11*-2=-22 12*-3=-36 This is not my definition, it is : f(n)=n*((n+1) mod 10)), meaning : 2*3=6 3*4=12 4*5=20 5*6=30 6*7=42 7*8=56 8*9=72 9*0=0 10*1=10 11*2=22 12*3=36 And even if it was, the fact that the definition is verified for 2,3,4,5,6 validate the definition, wich is the question asked. Nobody asked the solution must be a constant curve or anything else, it have to verify 2->6 3->12 4->20 5->30 6->42 That's all Anonymous Coward 27582823 Agreed, please I am not saying you are wrong, your math is sound. I am using extrapolation and looking for the best pattern match ie constant curve given the initial data set. I tend to process numbers in a graphical and even colorful way. But I like the way you processed it as well. |

Anonymous Coward User ID: 27582823 France 11/15/2013 11:04 PM Report Abusive Post Report Copyright Violation | Reminder for new page and new comers. Correct answers so far Quoting: If f(2)=12, f(3)=12, f(4)=20, f(5)=30, f(6)=42, define f(n) and give f(9) a) f(n)=n*(n+1) so f(9)=9*10=90 b) with [n] = nth prime number, f(n)=[n]+[2n-2] so f(9)=[9]+[2*9-2]=23+[16]=23+53=76 c) f(n) = n * ((n+1) modulo 10)) so f(9) = 9 * (10 modulo 10) = 9 * 0 = 0 There is also a strange cabal which insist saying 72 is correct but failing to define f(n). Anonymous Coward 27582823 you god damn french man doing things all long and drawn out and shit.. whats with all the algebraic non-sense.. couldn't you just see the pattern at a first glance or what? Anonymous Coward 17260532 Hi Canada, nice meeting you. The only pattern I see concerning 72 is there is a cabal here trying to get me doubting my sanity. I understand I post too much and I apology about that but this is also your fault. If someone give a correct 72 answer I will add it to the list and stay quiet. I have to believe you on word that 72 is correct ? All 72 answers have been un-justified or 'debunked' so far. |

Anonymous Coward User ID: 50023016 Canada 11/15/2013 11:05 PM Report Abusive Post Report Copyright Violation | |

The Clowns User ID: 30400765 United States 11/15/2013 11:05 PM Report Abusive Post Report Copyright Violation | |

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