The sun is randomly out of position. | |
74444 User ID: 74444 United States 07/14/2016 01:14 PM Report Abusive Post Report Copyright Violation | If you can prove that current models match known observations from the 19th and 20th century, then I will accept the sun is exactly where it should be. Quoting: Anonymous Coward 70216415 Why only *one* century? Stonehenge. Chichen Itza. Elephant's Tomb in Seville. Newgrange in Ireland. The Peru Pyramid. The Thirteen Towers in Chankillo. Current models match known observations from multiple times dating back both hundreds and thousands of years -- since all these observatories act predictably. QED. |
74444 User ID: 74444 United States 07/14/2016 01:16 PM Report Abusive Post Report Copyright Violation | |
Dr. Astro Senior Forum Moderator User ID: 72424007 United States 07/14/2016 01:26 PM Report Abusive Post Report Copyright Violation | This is really irrelevant to the discussion. The point is that basic observation should solve the debate. Since I'm assuming, you can't go back in time... then the very next best thing would be for you to actually pull up historical records and compare and contrast. You know, the basic ground work of science, i.e field work. You know, the hard shit.. and not punching a few keys into your gps controlled telescope. Quoting: Anonymous Coward 70216415 If you can prove that current models match known observations from the 19th and 20th century, then I will accept the sun is exactly where it should be. And, note: I am not asking for copy and paste hubris. In order to successfully prove your point, I will really be impressed if you actually went out and compared actual historical records, i.e. went to the library and came back to us all. You know... textual evidence. K, done. Here are my measurements of the sun this evening. First, here's a picture of the sun I shot on a tripod with my camera and a Thousand Oaks Type 2+ solar filter: Quoting: Dr. Astro [link to www.flickr.com (secure)] It was a bit cloudy, but still a serviceable photo for these purposes. EXIF data intact, the time zone is eastern time, 4 hours behind UT. I left the camera undisturbed for several hours and then took a 1 second exposure without the solar filter: [link to www.flickr.com (secure)] Yes, for convenience I was shooting through my window the whole time. Not going for pretty astrophotography here. I then layered the two images together so that the sun's previous position in the image could be directly seen in the second image. I also used dynamic background subtraction to remove the light pollution: [link to www.flickr.com (secure)] I astrometrically solved the image here: [link to nova.astrometry.net] The astrometry isn't perfect, but again, it's serviceable for our purposes. Note that the resolution of the image is 12 arcseconds per pixel. 20/20 vision is the ability to resolve a spatial separation of 1 minute of arc, 60 arcseconds, so this image is about 5 times higher in resolution than that. Now, I used my spreadsheet to calculate the expected location and geometric alt/az of the sun using Newcomb's theory: Input Year 2016 month 7 day 7 hour (UT) 23 minute 16 second 48 W Longitude (Decimal deg) 82 Latitude (Decimal deg) (N+, S-) 27 Height above sea level (meters) 0 Pressure (mb) 0 Temperature (Centigrade) 25 Solar Coordinates Apparent Right Ascension at Equinox of date Hours 7 Minutes 10 Seconds 27 Apparent Declination at Equinox of date Degrees 22 Minutes 26 Seconds 46 Altitude (degrees) 13.3992166 Azimuth (degrees, 0 North) 288.6105497 [link to dropcanvas.com] I then converted the geometric altitude and azimuth to J2000 equatorial coordinates at the time of the second photo: Input Year 2016 month 7 day 8 hour (UT) 2 minute 2 second 14 W Longitude (Decimal deg) 82 Latitude (Decimal deg) (N+, S-) 27 Height above sea level (meters) 0 Pressure (mb) 0 Temperature (Centigrade) 15 Convert to RA and Dec Geometric Altitude 13.3992166 Azimuth 288.6105497 RA J2000 9 55 25.28 Dec J2000 22 31 29.9 [link to dropcanvas.com] Plugging these numbers into the astrometrically solved image shows that the Sun's expected location (the green circle) matches its observed location: [link to www.flickr.com (secure)] And yes, I made my spreadsheet myself, this isn't just "copy/paste BS." The spreadsheet is based on Newcomb's numbers for calculating the position of the sun, using Jean Meeus' truncated method published decades ago. I used the actual book, from the library. [link to www.worldcat.org] You can verify it against Newcomb's own book as well: [link to www.worldcat.org] |
Dr. Feelgood User ID: 9734761 United Kingdom 07/14/2016 01:59 PM Report Abusive Post Report Copyright Violation | The earth is beginning to tilt back upon its TRUE norms relative to the sun. Quoting: Anonymous Coward 70216415 Yet the North Star *remains* the North star. This simple observation belies everything else you wrote. BTW you were asking me to explain to you about the Earth's topology. Here you go Thread: The sun is randomly out of position. (Page 19) |
Anonymous Coward User ID: 72571617 Norway 07/14/2016 02:12 PM Report Abusive Post Report Copyright Violation | This is really irrelevant to the discussion. The point is that basic observation should solve the debate. Since I'm assuming, you can't go back in time... then the very next best thing would be for you to actually pull up historical records and compare and contrast. You know, the basic ground work of science, i.e field work. You know, the hard shit.. and not punching a few keys into your gps controlled telescope. Quoting: Anonymous Coward 70216415 If you can prove that current models match known observations from the 19th and 20th century, then I will accept the sun is exactly where it should be. And, note: I am not asking for copy and paste hubris. In order to successfully prove your point, I will really be impressed if you actually went out and compared actual historical records, i.e. went to the library and came back to us all. You know... textual evidence. K, done. Here are my measurements of the sun this evening. First, here's a picture of the sun I shot on a tripod with my camera and a Thousand Oaks Type 2+ solar filter: Quoting: Dr. Astro [link to www.flickr.com (secure)] It was a bit cloudy, but still a serviceable photo for these purposes. EXIF data intact, the time zone is eastern time, 4 hours behind UT. I left the camera undisturbed for several hours and then took a 1 second exposure without the solar filter: [link to www.flickr.com (secure)] Yes, for convenience I was shooting through my window the whole time. Not going for pretty astrophotography here. I then layered the two images together so that the sun's previous position in the image could be directly seen in the second image. I also used dynamic background subtraction to remove the light pollution: [link to www.flickr.com (secure)] I astrometrically solved the image here: [link to nova.astrometry.net] The astrometry isn't perfect, but again, it's serviceable for our purposes. Note that the resolution of the image is 12 arcseconds per pixel. 20/20 vision is the ability to resolve a spatial separation of 1 minute of arc, 60 arcseconds, so this image is about 5 times higher in resolution than that. Now, I used my spreadsheet to calculate the expected location and geometric alt/az of the sun using Newcomb's theory: Input Year 2016 month 7 day 7 hour (UT) 23 minute 16 second 48 W Longitude (Decimal deg) 82 Latitude (Decimal deg) (N+, S-) 27 Height above sea level (meters) 0 Pressure (mb) 0 Temperature (Centigrade) 25 Solar Coordinates Apparent Right Ascension at Equinox of date Hours 7 Minutes 10 Seconds 27 Apparent Declination at Equinox of date Degrees 22 Minutes 26 Seconds 46 Altitude (degrees) 13.3992166 Azimuth (degrees, 0 North) 288.6105497 [link to dropcanvas.com] I then converted the geometric altitude and azimuth to J2000 equatorial coordinates at the time of the second photo: Input Year 2016 month 7 day 8 hour (UT) 2 minute 2 second 14 W Longitude (Decimal deg) 82 Latitude (Decimal deg) (N+, S-) 27 Height above sea level (meters) 0 Pressure (mb) 0 Temperature (Centigrade) 15 Convert to RA and Dec Geometric Altitude 13.3992166 Azimuth 288.6105497 RA J2000 9 55 25.28 Dec J2000 22 31 29.9 [link to dropcanvas.com] Plugging these numbers into the astrometrically solved image shows that the Sun's expected location (the green circle) matches its observed location: [link to www.flickr.com (secure)] And yes, I made my spreadsheet myself, this isn't just "copy/paste BS." The spreadsheet is based on Newcomb's numbers for calculating the position of the sun, using Jean Meeus' truncated method published decades ago. I used the actual book, from the library. [link to www.worldcat.org] You can verify it against Newcomb's own book as well: [link to www.worldcat.org] Wow I am impressed. You did exactly what the AC ask for. Even before he ask incredible. He must be impressed out of his boots. |
Dr. Feelgood User ID: 9734761 United Kingdom 07/14/2016 03:30 PM Report Abusive Post Report Copyright Violation | Where is the Sun and how long has it been rising there? "It seems like years since it's been here" Where is "here"? A particular spot on the horizon? A hidden message in plain sight? "Parecía como si la luz no había existido durante años" It seems the light has not existed for years? [link to www.youtube.com (secure)] |
Anonymous Coward User ID: 69340041 United States 07/14/2016 03:45 PM Report Abusive Post Report Copyright Violation | But the rest was impressive Dr Feelgood. Even though we where a few pages ahead before he got it all down. Quoting: Anonymous Coward 72573076 Got it. You are impressed by irrational mumbo-jumbo as long as you agree with the person viewpoint. Look up confirmation bias. Wait what?? I don't agree with his viewpoint. The opposing view if you bothered to read his eloquent post. So you don't believe the Earth tilted then. |
Anonymous Coward User ID: 69340041 United States 07/14/2016 03:55 PM Report Abusive Post Report Copyright Violation | Here is a rather clever idea. Instead of basing your conclusion on where the sun "should" be right now, why not just go to primary texts and check for yourself. Quoting: Anonymous Coward 70216415 I mean, the 19th and 20th centuries are replete with what were called farmer's almanacs which actually recorded celestial events. Note: I said, they "recorded." You get that? In other words, you would have a vast literature unto which you could base any current day observation. Lemme know when you have bothered to do that. Do they record the Sun's colour? . *color* And why the extra period for no reason? Not very grammatically correct. |
Anonymous Coward User ID: 69340041 United States 07/14/2016 03:58 PM Report Abusive Post Report Copyright Violation | Prøve it please. This is info was provided by the good Dr V Tepes By rules of logic, he has to prove what he says is correct. I do not have to prove what he says is wrong. He has provided no such proof. |
Dr. Feelgood User ID: 9734761 United Kingdom 07/14/2016 04:01 PM Report Abusive Post Report Copyright Violation | Here is a rather clever idea. Instead of basing your conclusion on where the sun "should" be right now, why not just go to primary texts and check for yourself. Quoting: Anonymous Coward 70216415 I mean, the 19th and 20th centuries are replete with what were called farmer's almanacs which actually recorded celestial events. Note: I said, they "recorded." You get that? In other words, you would have a vast literature unto which you could base any current day observation. Lemme know when you have bothered to do that. Do they record the Sun's colour? . *color* *colour* And why the extra period for no reason? Not very grammatically correct. Quoting: Anonymous Coward 69340041 It's a secret gang sign. |
Anonymous Coward User ID: 69340041 United States 07/14/2016 04:06 PM Report Abusive Post Report Copyright Violation | Here is a rather clever idea. Instead of basing your conclusion on where the sun "should" be right now, why not just go to primary texts and check for yourself. Quoting: Anonymous Coward 70216415 I mean, the 19th and 20th centuries are replete with what were called farmer's almanacs which actually recorded celestial events. Note: I said, they "recorded." You get that? In other words, you would have a vast literature unto which you could base any current day observation. Lemme know when you have bothered to do that. Do they record the Sun's colour? . *color* *colour* And why the extra period for no reason? Not very grammatically correct. Quoting: Anonymous Coward 69340041 It's a secret gang sign. *color* |
Dr Heyerdahl User ID: 72571617 Norway 07/14/2016 04:11 PM Report Abusive Post Report Copyright Violation | Prøve it please. This is info was provided by the good Dr V Tepes By rules of logic, he has to prove what he says is correct. I do not have to prove what he says is wrong. He has provided no such proof. Hmm logic like using NASA imagery with time stamps to prove his point? Where's your contradicting evidence? I'll take Dr V Tepes word over yours anyday. |
Anonymous Coward User ID: 72571617 Norway 07/14/2016 04:19 PM Report Abusive Post Report Copyright Violation | |
Anonymous Coward User ID: 69340041 United States 07/14/2016 04:29 PM Report Abusive Post Report Copyright Violation | By rules of logic, he has to prove what he says is correct. I do not have to prove what he says is wrong. He has provided no such proof. Hmm logic like using NASA imagery with time stamps to prove his point? Where's your contradicting evidence? I'll take Dr V Tepes word over yours anyday. It isn't the images. It is his interpretation. First off, he starts by assuming that the Earth is rather then allowing the data to speak for itself. It is called affirming the consequent. The biggest problem is that he doesn't know what a sun synchronous orbit is. [link to modis.gsfc.nasa.gov] [link to earthobservatory.nasa.gov] [link to www.encyclopedia.com] Understanding a sun synchronous orbit explains his observation completely without resorting to the wobbling Earth garbage. The northern hemisphere of Earth tilts toward the Sun June/July/August. It tilts away from the Sun in January/February/March. Since the satellite is oriented with the Sun, the Earth will seem to wobble back and forth throughout the year, which is exactly what he is showing. Just the effect of a Sun synchronous orbit. |
Anonymous Coward User ID: 69340041 United States 07/14/2016 04:31 PM Report Abusive Post Report Copyright Violation | |
Anonymous Coward User ID: 72571617 Norway 07/14/2016 04:36 PM Report Abusive Post Report Copyright Violation | By rules of logic, he has to prove what he says is correct. I do not have to prove what he says is wrong. He has provided no such proof. Hmm logic like using NASA imagery with time stamps to prove his point? Where's your contradicting evidence? I'll take Dr V Tepes word over yours anyday. It isn't the images. It is his interpretation. First off, he starts by assuming that the Earth is rather then allowing the data to speak for itself. It is called affirming the consequent. The biggest problem is that he doesn't know what a sun synchronous orbit is. [link to modis.gsfc.nasa.gov] [link to earthobservatory.nasa.gov] [link to www.encyclopedia.com] Understanding a sun synchronous orbit explains his observation completely without resorting to the wobbling Earth garbage. The northern hemisphere of Earth tilts toward the Sun June/July/August. It tilts away from the Sun in January/February/March. Since the satellite is oriented with the Sun, the Earth will seem to wobble back and forth throughout the year, which is exactly what he is showing. Just the effect of a Sun synchronous orbit. Only those images he is referring to are 24 hrs apart. Please pay attention |
Anonymous Coward User ID: 72571617 Norway 07/14/2016 04:38 PM Report Abusive Post Report Copyright Violation | Your rules of logic are illogical if they do not apply to yourself. Quoting: Anonymous Coward 72571617 That makes zero sense. My claim is nothing has changed. The extraordinary claim is that things have changed so he, and you, have to provide extraordinary evidence to prove your claim. You claim it was a fallacy by youtube. Now certainly we can apply your rules of logic to that statement and demand evidence of such claim. |
Anonymous Coward User ID: 69340041 United States 07/14/2016 04:50 PM Report Abusive Post Report Copyright Violation | ... Quoting: Anonymous Coward 69340041 By rules of logic, he has to prove what he says is correct. I do not have to prove what he says is wrong. He has provided no such proof. Hmm logic like using NASA imagery with time stamps to prove his point? Where's your contradicting evidence? I'll take Dr V Tepes word over yours anyday. It isn't the images. It is his interpretation. First off, he starts by assuming that the Earth is rather then allowing the data to speak for itself. It is called affirming the consequent. The biggest problem is that he doesn't know what a sun synchronous orbit is. [link to modis.gsfc.nasa.gov] [link to earthobservatory.nasa.gov] [link to www.encyclopedia.com] Understanding a sun synchronous orbit explains his observation completely without resorting to the wobbling Earth garbage. The northern hemisphere of Earth tilts toward the Sun June/July/August. It tilts away from the Sun in January/February/March. Since the satellite is oriented with the Sun, the Earth will seem to wobble back and forth throughout the year, which is exactly what he is showing. Just the effect of a Sun synchronous orbit. Only those images he is referring to are 24 hrs apart. Please pay attention Only one pair. The others are one orbit apart. |
Anonymous Coward User ID: 72571617 Norway 07/15/2016 04:00 AM Report Abusive Post Report Copyright Violation | ... Quoting: Dr Heyerdahl 72571617 Hmm logic like using NASA imagery with time stamps to prove his point? Where's your contradicting evidence? I'll take Dr V Tepes word over yours anyday. It isn't the images. It is his interpretation. First off, he starts by assuming that the Earth is rather then allowing the data to speak for itself. It is called affirming the consequent. The biggest problem is that he doesn't know what a sun synchronous orbit is. [link to modis.gsfc.nasa.gov] [link to earthobservatory.nasa.gov] [link to www.encyclopedia.com] Understanding a sun synchronous orbit explains his observation completely without resorting to the wobbling Earth garbage. The northern hemisphere of Earth tilts toward the Sun June/July/August. It tilts away from the Sun in January/February/March. Since the satellite is oriented with the Sun, the Earth will seem to wobble back and forth throughout the year, which is exactly what he is showing. Just the effect of a Sun synchronous orbit. Only those images he is referring to are 24 hrs apart. Please pay attention Only one pair. The others are one orbit apart. Irrelevant |
Anonymous Coward User ID: 69340041 United States 07/18/2016 11:32 AM Report Abusive Post Report Copyright Violation | ... Quoting: Anonymous Coward 69340041 It isn't the images. It is his interpretation. First off, he starts by assuming that the Earth is rather then allowing the data to speak for itself. It is called affirming the consequent. The biggest problem is that he doesn't know what a sun synchronous orbit is. [link to modis.gsfc.nasa.gov] [link to earthobservatory.nasa.gov] [link to www.encyclopedia.com] Understanding a sun synchronous orbit explains his observation completely without resorting to the wobbling Earth garbage. The northern hemisphere of Earth tilts toward the Sun June/July/August. It tilts away from the Sun in January/February/March. Since the satellite is oriented with the Sun, the Earth will seem to wobble back and forth throughout the year, which is exactly what he is showing. Just the effect of a Sun synchronous orbit. Only those images he is referring to are 24 hrs apart. Please pay attention Only one pair. The others are one orbit apart. Irrelevant The meaning of my post is completely lost on you, not surprising. You cannot say anything about the "wobble" of the Earth from satellite images if you do not know what sun synchronous means. You have to be able to understand the expect motion or, more correctly, orientation if you do not understand the orbital dynamics. The poster clearly did not understand the orbit so drawing conclusions from an orbit you do not understand results in meaningless drivel. |
Anonymous Coward User ID: 72483145 United States 07/18/2016 11:40 AM Report Abusive Post Report Copyright Violation | This is really irrelevant to the discussion. The point is that basic observation should solve the debate. Since I'm assuming, you can't go back in time... then the very next best thing would be for you to actually pull up historical records and compare and contrast. You know, the basic ground work of science, i.e field work. You know, the hard shit.. and not punching a few keys into your gps controlled telescope. Quoting: Anonymous Coward 70216415 If you can prove that current models match known observations from the 19th and 20th century, then I will accept the sun is exactly where it should be. And, note: I am not asking for copy and paste hubris. In order to successfully prove your point, I will really be impressed if you actually went out and compared actual historical records, i.e. went to the library and came back to us all. You know... textual evidence. K, done. Here are my measurements of the sun this evening. First, here's a picture of the sun I shot on a tripod with my camera and a Thousand Oaks Type 2+ solar filter: Quoting: Dr. Astro [link to www.flickr.com (secure)] It was a bit cloudy, but still a serviceable photo for these purposes. EXIF data intact, the time zone is eastern time, 4 hours behind UT. I left the camera undisturbed for several hours and then took a 1 second exposure without the solar filter: [link to www.flickr.com (secure)] Yes, for convenience I was shooting through my window the whole time. Not going for pretty astrophotography here. I then layered the two images together so that the sun's previous position in the image could be directly seen in the second image. I also used dynamic background subtraction to remove the light pollution: [link to www.flickr.com (secure)] I astrometrically solved the image here: [link to nova.astrometry.net] The astrometry isn't perfect, but again, it's serviceable for our purposes. Note that the resolution of the image is 12 arcseconds per pixel. 20/20 vision is the ability to resolve a spatial separation of 1 minute of arc, 60 arcseconds, so this image is about 5 times higher in resolution than that. Now, I used my spreadsheet to calculate the expected location and geometric alt/az of the sun using Newcomb's theory: Input Year 2016 month 7 day 7 hour (UT) 23 minute 16 second 48 W Longitude (Decimal deg) 82 Latitude (Decimal deg) (N+, S-) 27 Height above sea level (meters) 0 Pressure (mb) 0 Temperature (Centigrade) 25 Solar Coordinates Apparent Right Ascension at Equinox of date Hours 7 Minutes 10 Seconds 27 Apparent Declination at Equinox of date Degrees 22 Minutes 26 Seconds 46 Altitude (degrees) 13.3992166 Azimuth (degrees, 0 North) 288.6105497 [link to dropcanvas.com] I then converted the geometric altitude and azimuth to J2000 equatorial coordinates at the time of the second photo: Input Year 2016 month 7 day 8 hour (UT) 2 minute 2 second 14 W Longitude (Decimal deg) 82 Latitude (Decimal deg) (N+, S-) 27 Height above sea level (meters) 0 Pressure (mb) 0 Temperature (Centigrade) 15 Convert to RA and Dec Geometric Altitude 13.3992166 Azimuth 288.6105497 RA J2000 9 55 25.28 Dec J2000 22 31 29.9 [link to dropcanvas.com] Plugging these numbers into the astrometrically solved image shows that the Sun's expected location (the green circle) matches its observed location: [link to www.flickr.com (secure)] And yes, I made my spreadsheet myself, this isn't just "copy/paste BS." The spreadsheet is based on Newcomb's numbers for calculating the position of the sun, using Jean Meeus' truncated method published decades ago. I used the actual book, from the library. [link to www.worldcat.org] You can verify it against Newcomb's own book as well: [link to www.worldcat.org] This is unrelated, or not, but my family was at a BBQ on the 15th, there was a visible planet, in broad daylight, as it was around 6 pm in Southern Idaho. We couldn't figure out what it was at first, but it didn't move. It was fairly large too, as planets go in the daytime☻. I have looked and found something on Venus being visible durning the daytime but that was a few years ago. Anyone else see this? It was visible toward the SW. I haven't been able to spot it again but I have a lot of trees at my house. |
Anonymous Coward User ID: 69340041 United States 07/18/2016 03:43 PM Report Abusive Post Report Copyright Violation | This is unrelated, or not, but my family was at a BBQ on the 15th, there was a visible planet, in broad daylight, as it was around 6 pm in Southern Idaho. We couldn't figure out what it was at first, but it didn't move. It was fairly large too, as planets go in the daytime☻. I have looked and found something on Venus being visible durning the daytime but that was a few years ago. Anyone else see this? It was visible toward the SW. I haven't been able to spot it again but I have a lot of trees at my house. Quoting: Anonymous Coward 72483145 Here is a very simple to use planetarium program. [link to neave.com] Just enter your location on the map and you can change the date and time to see what is in the sky at that time. Good luck. |
Dr. Astro Senior Forum Moderator User ID: 4211721 United States 07/20/2016 03:46 PM Report Abusive Post Report Copyright Violation | This is really irrelevant to the discussion. The point is that basic observation should solve the debate. Since I'm assuming, you can't go back in time... then the very next best thing would be for you to actually pull up historical records and compare and contrast. You know, the basic ground work of science, i.e field work. You know, the hard shit.. and not punching a few keys into your gps controlled telescope. Quoting: Anonymous Coward 70216415 If you can prove that current models match known observations from the 19th and 20th century, then I will accept the sun is exactly where it should be. And, note: I am not asking for copy and paste hubris. In order to successfully prove your point, I will really be impressed if you actually went out and compared actual historical records, i.e. went to the library and came back to us all. You know... textual evidence. K, done. Here are my measurements of the sun this evening. First, here's a picture of the sun I shot on a tripod with my camera and a Thousand Oaks Type 2+ solar filter: Quoting: Dr. Astro [link to www.flickr.com (secure)] It was a bit cloudy, but still a serviceable photo for these purposes. EXIF data intact, the time zone is eastern time, 4 hours behind UT. I left the camera undisturbed for several hours and then took a 1 second exposure without the solar filter: [link to www.flickr.com (secure)] Yes, for convenience I was shooting through my window the whole time. Not going for pretty astrophotography here. I then layered the two images together so that the sun's previous position in the image could be directly seen in the second image. I also used dynamic background subtraction to remove the light pollution: [link to www.flickr.com (secure)] I astrometrically solved the image here: [link to nova.astrometry.net] The astrometry isn't perfect, but again, it's serviceable for our purposes. Note that the resolution of the image is 12 arcseconds per pixel. 20/20 vision is the ability to resolve a spatial separation of 1 minute of arc, 60 arcseconds, so this image is about 5 times higher in resolution than that. Now, I used my spreadsheet to calculate the expected location and geometric alt/az of the sun using Newcomb's theory: Input Year 2016 month 7 day 7 hour (UT) 23 minute 16 second 48 W Longitude (Decimal deg) 82 Latitude (Decimal deg) (N+, S-) 27 Height above sea level (meters) 0 Pressure (mb) 0 Temperature (Centigrade) 25 Solar Coordinates Apparent Right Ascension at Equinox of date Hours 7 Minutes 10 Seconds 27 Apparent Declination at Equinox of date Degrees 22 Minutes 26 Seconds 46 Altitude (degrees) 13.3992166 Azimuth (degrees, 0 North) 288.6105497 [link to dropcanvas.com] I then converted the geometric altitude and azimuth to J2000 equatorial coordinates at the time of the second photo: Input Year 2016 month 7 day 8 hour (UT) 2 minute 2 second 14 W Longitude (Decimal deg) 82 Latitude (Decimal deg) (N+, S-) 27 Height above sea level (meters) 0 Pressure (mb) 0 Temperature (Centigrade) 15 Convert to RA and Dec Geometric Altitude 13.3992166 Azimuth 288.6105497 RA J2000 9 55 25.28 Dec J2000 22 31 29.9 [link to dropcanvas.com] Plugging these numbers into the astrometrically solved image shows that the Sun's expected location (the green circle) matches its observed location: [link to www.flickr.com (secure)] And yes, I made my spreadsheet myself, this isn't just "copy/paste BS." The spreadsheet is based on Newcomb's numbers for calculating the position of the sun, using Jean Meeus' truncated method published decades ago. I used the actual book, from the library. [link to www.worldcat.org] You can verify it against Newcomb's own book as well: [link to www.worldcat.org] Wow I am impressed. You did exactly what the AC ask for. Even before he ask incredible. He must be impressed out of his boots. He said what he said precisely because he knows that's exactly what I already did. He's a troll. He gets off on contradicting me, even when I'm providing exactly what he's asking for. I guess he got bored with your thread. I was expecting him to come on and offer some lame ass excuse for why what I was providing was not appropriate even though it's exactly what he's describing. |
74444 User ID: 74444 United States 07/20/2016 06:11 PM Report Abusive Post Report Copyright Violation | This is really irrelevant to the discussion. The point is that basic observation should solve the debate. Since I'm assuming, you can't go back in time... then the very next best thing would be for you to actually pull up historical records and compare and contrast. You know, the basic ground work of science, i.e field work. You know, the hard shit.. and not punching a few keys into your gps controlled telescope. Quoting: Anonymous Coward 70216415 If you can prove that current models match known observations from the 19th and 20th century, then I will accept the sun is exactly where it should be. And, note: I am not asking for copy and paste hubris. In order to successfully prove your point, I will really be impressed if you actually went out and compared actual historical records, i.e. went to the library and came back to us all. You know... textual evidence. K, done. Here are my measurements of the sun this evening. First, here's a picture of the sun I shot on a tripod with my camera and a Thousand Oaks Type 2+ solar filter: Quoting: Dr. Astro [link to www.flickr.com (secure)] It was a bit cloudy, but still a serviceable photo for these purposes. EXIF data intact, the time zone is eastern time, 4 hours behind UT. I left the camera undisturbed for several hours and then took a 1 second exposure without the solar filter: [link to www.flickr.com (secure)] Yes, for convenience I was shooting through my window the whole time. Not going for pretty astrophotography here. I then layered the two images together so that the sun's previous position in the image could be directly seen in the second image. I also used dynamic background subtraction to remove the light pollution: [link to www.flickr.com (secure)] I astrometrically solved the image here: [link to nova.astrometry.net] The astrometry isn't perfect, but again, it's serviceable for our purposes. Note that the resolution of the image is 12 arcseconds per pixel. 20/20 vision is the ability to resolve a spatial separation of 1 minute of arc, 60 arcseconds, so this image is about 5 times higher in resolution than that. Now, I used my spreadsheet to calculate the expected location and geometric alt/az of the sun using Newcomb's theory: Input Year 2016 month 7 day 7 hour (UT) 23 minute 16 second 48 W Longitude (Decimal deg) 82 Latitude (Decimal deg) (N+, S-) 27 Height above sea level (meters) 0 Pressure (mb) 0 Temperature (Centigrade) 25 Solar Coordinates Apparent Right Ascension at Equinox of date Hours 7 Minutes 10 Seconds 27 Apparent Declination at Equinox of date Degrees 22 Minutes 26 Seconds 46 Altitude (degrees) 13.3992166 Azimuth (degrees, 0 North) 288.6105497 [link to dropcanvas.com] I then converted the geometric altitude and azimuth to J2000 equatorial coordinates at the time of the second photo: Input Year 2016 month 7 day 8 hour (UT) 2 minute 2 second 14 W Longitude (Decimal deg) 82 Latitude (Decimal deg) (N+, S-) 27 Height above sea level (meters) 0 Pressure (mb) 0 Temperature (Centigrade) 15 Convert to RA and Dec Geometric Altitude 13.3992166 Azimuth 288.6105497 RA J2000 9 55 25.28 Dec J2000 22 31 29.9 [link to dropcanvas.com] Plugging these numbers into the astrometrically solved image shows that the Sun's expected location (the green circle) matches its observed location: [link to www.flickr.com (secure)] And yes, I made my spreadsheet myself, this isn't just "copy/paste BS." The spreadsheet is based on Newcomb's numbers for calculating the position of the sun, using Jean Meeus' truncated method published decades ago. I used the actual book, from the library. [link to www.worldcat.org] You can verify it against Newcomb's own book as well: [link to www.worldcat.org] 415 never replied? Shocking. |