Godlike Productions - Reply to Thread

Users Online Now: 1,930 (Who's On?)	Visitors Today: 406,764
Pageviews Today: 699,054	Threads Today: 331	Posts Today: 4,778
08:13 AM

REPLY TO THREAD

Subject YU55 Closest Approach Distance Will Be 0.0000416667AU = 3904 miles -> NASA Lying<--

User Name

Font color: Font:

In accordance with industry accepted best practices we ask that users limit their copy / paste of copyrighted material to the relevant portions of the article you wish to discuss and no more than 50% of the source material, provide a link back to the original article and provide your original comments / criticism in your post with the article.

[quote:Anonymous Coward 4868206:MV8xNjk1NzE2XzI4MDI3Nzk0Xzc4ODYzOEIy]
[quote:Anonymous Coward 1707881:MV8xNjk1NzE2XzI4MDI3NzcxXzk2NkZFMUIz]
[quote:Anonymous Coward 4465388:MV8xNjk1NzE2XzI4MDI3MDg3X0ZEREI0RUND]
GET THIS PEOPLE! WHEN MEASURING THE DISTANCE BETWEEN TWO HEAVENLY BODIES, THE MEASUREMENTS ARE MADE FROM THE MIDDLE OF ONE BODY TO THE MIDDLE OF THE OTHER BODY.  OP CALCULATES A DISTANCE FROM THE EARTH TO YU55 AS 3904 MILES, CENTER TO CENTER. THE DIAMETER OF THE EARTH IS 7923 MILES. IF YOU TAKE 1/2 OF THE EARTH'S DIAMETER WHICH IS EQUAL TO 3861 MILES (THE DISTANCE FROM THE CENTER TO THE EDGE) AND 1/2 OF THE DIAMETER OF YU55 WHICH IS EQUAL TO 650 FEET OR APPROX. 1/9 OF A MILE, THEN YOU BASICALLY HAVE A MISS DISTANCE OF 43 FEET. FACTOR IN ATMOSPHERIC DRAG, AND YOU HAVE IMPACT PEOPLE! [b]IMPACT!
[/quote]

so....no doom?
[/quote]

At closest approach on Tuesday at 3:28 pm PST (23:28 UT), the 400m-wide space rock will be 324,600 kilometers away, about 85% the distance from Earth to the Moon.
[/quote]

Original Message From another site:

I am an engineer and my job involves various approaches to manipulating and analyzing data. I have this macro tool i use to interpolate and extrapolate data. So I took the distances of YU55 between Nov 4 - 11 (according to JPL, the close approach data is Nov 9 at 0.0022AU). Therefore, i get the following dataset:

Date Ref App Dist.
4 -5 0.0391
5 -4 0.0312
6 -3 0.0234
7 -2 0.0156
8 -1 0.0079
9 0 0.0022
10 1 0.0085
11 2 0.0162

Then I interpolate a per hour basis. So it looks something like:

Date Ref App Dist.
4 -5 -0.0391
-4.958333333 -0.038770833
-4.916666667 -0.038441667
-4.875 -0.0381125
... ... ...

Now think about this for a second... First of all, over a 7 day period, the trajectories of these two bodies are going to be relatively linear (straight). Therefore, the relative distance between the two will be linear as well (no corealis or angular acceleration or anything like that). Therefore, I should not see any significant disturbances in the data.
Secondly, the day to day distance given by jpl is taken at a 24 hr interval. Everything in between, they interpolate (supposedly just like I did). I compared their hour by hour distance to my interpolated data. All was spot on Until I got to the 8th (day before/of close approach). I observed that their distance decayed much more slowly than mine. So I created the following data. Notice, i applied the use of negative and positive distance to account for distance before and after close approach:

4 -5 -0.0391
5 -4 -0.0312
6 -3 -0.0234
7 -2 -0.0156
8 -1 -0.0079
9 0 0.0022
10 1 0.0085
11 2 0.0162

And came up with this during the course of Nov 8th:

8 -1 -0.0079
-0.958333333 -0.007479167
-0.916666667 -0.007058333
-0.875 -0.0066375
-0.833333333 -0.006216667
-0.791666667 -0.005795833
-0.75 -0.005375
-0.708333333 -0.004954167
-0.666666667 -0.004533333
-0.625 -0.0041125
-0.583333333 -0.003691667
-0.541666667 -0.003270833
-0.5 -0.00285
-0.458333333 -0.002429167
-0.416666667 -0.002008333
-0.375 -0.0015875
-0.333333333 -0.001166667
-0.291666667 -0.000745833
-0.25 -0.000325
-0.208333333 9.58333E-05
-0.166666667 0.000516667
-0.125 0.0009375
-0.083333333 0.001358333
-0.041666667 0.001779167
9 0 0.0022

finish it here [link to www.myweathertech.com]

Pictures (click to insert)





\| Next Page >>