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Globe Earth debunked
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[quote:Dr. Deplorable Astromut:MV8zOTk1MjYyXzcyMzYxODk4X0FCRDhDRDJC] [quote:Anonymous Coward 77443056:MV8zOTk1MjYyXzcyMzYxNTQxXzZGNzI5ODkx] [quote:Dr. Deplorable Astromut:MV8zOTk1MjYyXzcyMzYxNDg5X0NDREUzNTk4] [quote:Anonymous Coward 77443056:MV8zOTk1MjYyXzcyMzYxMzg2XzU5MkUzRThD] [quote:Dr. Deplorable Astromut:MV8zOTk1MjYyXzcyMzYwMDQzXzNGMEI1QzMz] [quote:Anonymous Coward 77456542:MV8zOTk1MjYyXzcyMzU5OTQxX0U0N0MzM0NB] [quote:Dr. Deplorable Astromut:MV8zOTk1MjYyXzcyMzU5NzY5X0QyMEZGNDcw] [quote:Anonymous Coward 77456453:MV8zOTk1MjYyXzcyMzU5NjE4X0VCOEIzODE2] The equation states that mass flow in an area is a force. Exit velocity no longer matters. Just mass flow and pipe diameter. [/quote] Wrong. Thanks for continuing to prove your ignorance. Exit velocity is in the original equation, just because you try to substitute something else equal to it does not render the original equation invalid. The velocity of the reaction mass matters. Thank you for continuing to prove how stupid you are. [quote:Idiot] In order for the weight to leave my hand, the weight has to move (velocity). [/quote] Nope. You let go, the instantaneous velocity is 0, you only released it, you didn't throw it. Velocity starts increasing AFTER your hand has released it. [/quote] Yes it does because it shows that the NASA thrust equation is simply stating mass flow rate is force. This is wrong. [/quote] Wrong. You can't have "mass flow rate" without velocity. https://www.grc.nasa.gov/www/k-12/airplane/mflow.html [quote:fuckingretard] I’m holding the weight between two finger. The weight is contacting my fingers and the hand space between the two fingers. I move one finger, the wieght moves away from the hand space between the two fingers and falls sliding down the finger I didn’t move. How did the wieght move away from my finger if the velocity was 0? Where’s the opposite force? [/quote] So apparently you failed basic physics and never understood basic force diagrams even for simple cases, like rolling something off a ramp. http://www.physics.usyd.edu.au/super/physics_tut/activities/Mechanics/Accelerating_on_a_Ramp.pdf Got it. That doesn't change the fact that you're dead wrong and physics works just fine. But for the previous example if you simply let a weight go it will have no velocity at the moment you release it. Now you're trying to change the example since I proved you wrong. [/quote] So you are just going to ignore the part where velocity was substituted out of the equation? [/quote] Exit velocity is in the original equation, just because you try to substitute something else equal to it does not render the original equation invalid. The velocity of the reaction mass matters. You can't have "mass flow rate" without velocity. https://www.grc.nasa.gov/www/k-12/airplane/mflow.html [/quote] I didn’t try, I did. Using a valid equation. The end result is that it doesn’t work because one equation is wrong. That equation is the nasa equation [/quote] Nope. The equation works just fine, substituting in a more complex formula for the velocity of the fluid does not change the fact that the result still varies with the velocity of the fluid. Adjusting exit velocity still reduces the force, you're just trying to obfuscate it by substituting a formula for the velocity of a fluid in a pipe for the exit velocity. Exit velocity equals Me * sqrt (gamma * R * Te) where Te = exit temperature R = gas constant gamma = specific heat ratio Me = mach number If I substitute the above equation into the original formula it doesn't change the fact that exit velocity still matters, I've just substituted in a formula that equals the same thing. [/quote]
Original Message
Globe earth is an idea, with no proof or evidence.
let the nonsensical excuses begin...……………..
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