If the moon were hit, I cannot do the math, but I know its orbit would be greatly affected, and its pull on earth would be modified. Quoting: humuhumubannedbutgotthrough 3209328
Who are you trying to fool here?
Let's actually do the maths.
A back-of-the-envelope first Order of Magnitude calculation.
For simplicity we'll presume the asteroid is a cube 1 kilometre to a side, mostly made of lead, to get an average density 10 grammes per cubic centimetre, moving at a preposterous 100 km/s.
The mass of such an object would be 100,000(cm)^3 * 0.01 (kg/cm^3) = 10,000,000,000,000 kg or 10 billion tonnes.
The mass of the Moon is something like 7.35 × 10^22 kg
Which is 7,350,000,000 times as much.
So in a perfectly inelastic collision the object can transfer 1/7,350,000,000 of its velocity on the Moon.
Which gets me 0.0136 millimetre per second.
There's a reason engineers and scientists call doing an OOM calculation a sanity check.
BTW, have you seen
the size of some of the craters on the Moon?