Globe Earth debunked | |
LHP598 User ID: 77436004 United States 03/14/2019 08:12 AM Report Abusive Post Report Copyright Violation | You don't need an equation to show that "for every action there is an equal and opposite reaction". In fact, having an equation can confuse the issue, because the equation may pertain to an issue not related to the action reaction principle. Does math confuse you? Perhaps rocket science isn’t your thing. As for “every reaction has an equal and opposite reaction” You are saying that a person that weighs 75kg is deadlifting 100kg and he drops it from a height. Did the person get lifted off the ground? Because that’s basically what you are saying its cute that you think dropping an object where the movement comes from an outside force is the same as a highly energetic continuous explosion and expansion of fuel. If you have to insist that you've won an Internet argument, you've probably lost badly. - Danth's Law |
Anonymous Coward User ID: 33790028 United Kingdom 03/14/2019 08:21 AM Report Abusive Post Report Copyright Violation | I'll be staying to my own threads from now on and you won't have to be bothered by all these "hidden posts" you can't handle, except for my threads. Quoting: Dr. Deplorable Astromut Awwwww... It's for a good reason, a very positive thing has come up but I won't be able to reveal what it is for quite a while. You guys keep fighting the good fight though. Fight whoever you want. Objective reality really isn't up for an argument, fight or debate it just is what it is. |
Dr. Deplorable Astromut Senior Forum Moderator 03/14/2019 09:01 AM Report Abusive Post Report Copyright Violation | I'll be staying to my own threads from now on and you won't have to be bothered by all these "hidden posts" you can't handle, except for my threads. Quoting: Dr. Deplorable Astromut Awwwww... It's for a good reason, a very positive thing has come up but I won't be able to reveal what it is for quite a while. You guys keep fighting the good fight though. Fight whoever you want. Objective reality really isn't up for an argument, fight or debate it just is what it is. You have no idea what this is about and I wasn't talking to you so shut the fuk up. |
Anonymous Coward User ID: 77456453 Canada 03/14/2019 09:52 AM Report Abusive Post Report Copyright Violation | |
Dr. Deplorable Astromut Senior Forum Moderator 03/14/2019 09:55 AM Report Abusive Post Report Copyright Violation | Yes, they do. And in the second video you dishonestly ignore it's already in space to start with. The second video looks like a video game from the early 90s No, it does not. It shows a satellite being inserted into geostationary orbit. The telescope is tracking it based on its transfer orbit and the satellite is rapidly accelerated out of the view when the engine is lit to insert it into its final orbit. Your insults carry no weight. |
Anonymous Coward User ID: 77456453 Canada 03/14/2019 09:57 AM Report Abusive Post Report Copyright Violation | You don't need an equation to show that "for every action there is an equal and opposite reaction". In fact, having an equation can confuse the issue, because the equation may pertain to an issue not related to the action reaction principle. Does math confuse you? Perhaps rocket science isn’t your thing. As for “every reaction has an equal and opposite reaction” You are saying that a person that weighs 75kg is deadlifting 100kg and he drops it from a height. Did the person get lifted off the ground? Because that’s basically what you are saying Vacuuming a hole in the side of a tube on earth isn't proving the math of spaceflight wrong, it's just demonstrating a massive ignorance of force vectors. As is your example. What is the velocity of the weight the moment he lets go? 0 m/s. Doesn't matter if it accelerates to the ground after that, the velocity of the mass was nil when it left his hands. You don't even understand how f=ma works. The equation states that mass flow in an area is a force. Exit velocity no longer matters. Just mass flow and pipe diameter. In order for the weight to leave my hand, the weight has to move (velocity). Otherwise it would still be in contact with the tip of the finger i didn’t let go. Gravity and pressure are both potential energies. Movement occurs when You release it |
Dr. Deplorable Astromut Senior Forum Moderator 03/14/2019 10:13 AM Report Abusive Post Report Copyright Violation | The equation states that mass flow in an area is a force. Exit velocity no longer matters. Just mass flow and pipe diameter. Quoting: Anonymous Coward 77456453 Wrong. Thanks for continuing to prove your ignorance. Exit velocity is in the original equation, just because you try to substitute something else equal to it does not render the original equation invalid. The velocity of the reaction mass matters. Thank you for continuing to prove how stupid you are. In order for the weight to leave my hand, the weight has to move (velocity). Quoting: IdiotNope. You let go, the instantaneous velocity is 0, you only released it, you didn't throw it. Velocity starts increasing AFTER your hand has released it. |
Anonymous Coward User ID: 77456542 Canada 03/14/2019 10:29 AM Report Abusive Post Report Copyright Violation | The equation states that mass flow in an area is a force. Exit velocity no longer matters. Just mass flow and pipe diameter. Quoting: Anonymous Coward 77456453 Wrong. Thanks for continuing to prove your ignorance. Exit velocity is in the original equation, just because you try to substitute something else equal to it does not render the original equation invalid. The velocity of the reaction mass matters. Thank you for continuing to prove how stupid you are. In order for the weight to leave my hand, the weight has to move (velocity). Quoting: IdiotNope. You let go, the instantaneous velocity is 0, you only released it, you didn't throw it. Velocity starts increasing AFTER your hand has released it. Yes it does because it shows that the NASA thrust equation is simply stating mass flow rate is force. This is wrong. I’m holding the weight between two finger. The weight is contacting my fingers and the hand space between the two fingers. I move one finger, the wieght moves away from the hand space between the two fingers and falls sliding down the finger I didn’t move. How did the wieght move away from my finger if the velocity was 0? Where’s the opposite force? |
Dr. Deplorable Astromut Senior Forum Moderator 03/14/2019 10:41 AM Report Abusive Post Report Copyright Violation | The equation states that mass flow in an area is a force. Exit velocity no longer matters. Just mass flow and pipe diameter. Quoting: Anonymous Coward 77456453 Wrong. Thanks for continuing to prove your ignorance. Exit velocity is in the original equation, just because you try to substitute something else equal to it does not render the original equation invalid. The velocity of the reaction mass matters. Thank you for continuing to prove how stupid you are. In order for the weight to leave my hand, the weight has to move (velocity). Quoting: IdiotNope. You let go, the instantaneous velocity is 0, you only released it, you didn't throw it. Velocity starts increasing AFTER your hand has released it. Yes it does because it shows that the NASA thrust equation is simply stating mass flow rate is force. This is wrong. Wrong. You can't have "mass flow rate" without velocity. [link to www.grc.nasa.gov (secure)] I’m holding the weight between two finger. The weight is contacting my fingers and the hand space between the two fingers. I move one finger, the wieght moves away from the hand space between the two fingers and falls sliding down the finger I didn’t move. How did the wieght move away from my finger if the velocity was 0? Where’s the opposite force? Quoting: fuckingretardSo apparently you failed basic physics and never understood basic force diagrams even for simple cases, like rolling something off a ramp. [link to www.physics.usyd.edu.au] Got it. That doesn't change the fact that you're dead wrong and physics works just fine. But for the previous example if you simply let a weight go it will have no velocity at the moment you release it. Now you're trying to change the example since I proved you wrong. |
Anonymous Coward User ID: 72810610 United States 03/14/2019 10:54 AM Report Abusive Post Report Copyright Violation | Grab two pairs of polarizing sunglasses Line them up and look directly above you into the sky when the sun is at 10 o clock relative to your position Rayleigh scattering predicts light will be polarized linearly when traveling through a spherical medium i.e. the atmosphere because of nitrogen/oxygen dipole transmittance. A jones vector matrix reduction can quickly show this Tell me what happens when you rotate the sunglasses perpendicular to each other. Come back here with your results.. |
Remedial_Rebel User ID: 77275768 United States 03/14/2019 11:23 AM Report Abusive Post Report Copyright Violation | Yes it does because it shows that the NASA thrust equation is simply stating mass flow rate is force. This is wrong. Quoting: Anonymous Coward 77456542 Here's something that maybe, just maybe you'll understand.... Since you like FE university of youtube, Explain the movement of the water hose........ [link to www.youtube.com (secure)] Any objective person will conclude the flow of water is causing opposite reaction force that makes the hose move. Mass flow rate is force. This is high school physics. Last Edited by Remedial_Rebel on 03/14/2019 11:28 AM |
Anonymous Coward User ID: 73852158 United States 03/14/2019 11:50 AM Report Abusive Post Report Copyright Violation | |
Dr. Deplorable Astromut Senior Forum Moderator 03/14/2019 11:52 AM Report Abusive Post Report Copyright Violation | |
Anonymous Coward User ID: 75473435 United States 03/14/2019 12:20 PM Report Abusive Post Report Copyright Violation | |
Anonymous Coward User ID: 74770227 United States 03/14/2019 12:22 PM Report Abusive Post Report Copyright Violation | |
Anonymous Coward User ID: 77443056 Canada 03/14/2019 12:33 PM Report Abusive Post Report Copyright Violation | The equation states that mass flow in an area is a force. Exit velocity no longer matters. Just mass flow and pipe diameter. Quoting: Anonymous Coward 77456453 Wrong. Thanks for continuing to prove your ignorance. Exit velocity is in the original equation, just because you try to substitute something else equal to it does not render the original equation invalid. The velocity of the reaction mass matters. Thank you for continuing to prove how stupid you are. In order for the weight to leave my hand, the weight has to move (velocity). Quoting: IdiotNope. You let go, the instantaneous velocity is 0, you only released it, you didn't throw it. Velocity starts increasing AFTER your hand has released it. Yes it does because it shows that the NASA thrust equation is simply stating mass flow rate is force. This is wrong. Wrong. You can't have "mass flow rate" without velocity. [link to www.grc.nasa.gov (secure)] I’m holding the weight between two finger. The weight is contacting my fingers and the hand space between the two fingers. I move one finger, the wieght moves away from the hand space between the two fingers and falls sliding down the finger I didn’t move. How did the wieght move away from my finger if the velocity was 0? Where’s the opposite force? Quoting: fuckingretardSo apparently you failed basic physics and never understood basic force diagrams even for simple cases, like rolling something off a ramp. [link to www.physics.usyd.edu.au] Got it. That doesn't change the fact that you're dead wrong and physics works just fine. But for the previous example if you simply let a weight go it will have no velocity at the moment you release it. Now you're trying to change the example since I proved you wrong. So you are just going to ignore the part where velocity was substituted out of the equation? And then you are saying I failed at physics without refuting anything with reason |
Anonymous Coward User ID: 77443056 Canada 03/14/2019 12:33 PM Report Abusive Post Report Copyright Violation | Yes it does because it shows that the NASA thrust equation is simply stating mass flow rate is force. This is wrong. Quoting: Anonymous Coward 77456542 Here's something that maybe, just maybe you'll understand.... Since you like FE university of youtube, Explain the movement of the water hose........ [link to www.youtube.com (secure)] Any objective person will conclude the flow of water is causing opposite reaction force that makes the hose move. Mass flow rate is force. This is high school physics. Can you rule out with evidence that it is not pushing off air? |
Remedial_Rebel User ID: 77275768 United States 03/14/2019 12:34 PM Report Abusive Post Report Copyright Violation | There is no scientific proof of a spinning water ball Earth in a vacuum. There is no observable Earth curvature. No curvature then not a ball, not a ball then you cannot call the Earth a sphere. Quoting: Anonymous Coward 73852158 Total BullSh!t I have been off the coast of Atlantic City more times than I can remember and watched the Casinos (200ft high)sink into ocean going out and rise out coming back. To say this is optical parallax is a total fallacy. Any optical engineer who designs telescopes, binoculars, cameras, knows optical parallax can not possible cause an optical eclipse. This is true for sunsets and sunrises as well. An optical eclipse requires a physical obstruction. No matter what the distance, the most you will ever see from optical parallax, is objects (sun and horizon) will become tangent and nothing more. Last Edited by Remedial_Rebel on 03/14/2019 12:37 PM |
Dr. Deplorable Astromut Senior Forum Moderator 03/14/2019 12:40 PM Report Abusive Post Report Copyright Violation | ... Quoting: Dr. Deplorable Astromut Wrong. Thanks for continuing to prove your ignorance. Exit velocity is in the original equation, just because you try to substitute something else equal to it does not render the original equation invalid. The velocity of the reaction mass matters. Thank you for continuing to prove how stupid you are. ... Nope. You let go, the instantaneous velocity is 0, you only released it, you didn't throw it. Velocity starts increasing AFTER your hand has released it. Yes it does because it shows that the NASA thrust equation is simply stating mass flow rate is force. This is wrong. Wrong. You can't have "mass flow rate" without velocity. [link to www.grc.nasa.gov (secure)] I’m holding the weight between two finger. The weight is contacting my fingers and the hand space between the two fingers. I move one finger, the wieght moves away from the hand space between the two fingers and falls sliding down the finger I didn’t move. How did the wieght move away from my finger if the velocity was 0? Where’s the opposite force? Quoting: fuckingretardSo apparently you failed basic physics and never understood basic force diagrams even for simple cases, like rolling something off a ramp. [link to www.physics.usyd.edu.au] Got it. That doesn't change the fact that you're dead wrong and physics works just fine. But for the previous example if you simply let a weight go it will have no velocity at the moment you release it. Now you're trying to change the example since I proved you wrong. So you are just going to ignore the part where velocity was substituted out of the equation? Exit velocity is in the original equation, just because you try to substitute something else equal to it does not render the original equation invalid. The velocity of the reaction mass matters. You can't have "mass flow rate" without velocity. [link to www.grc.nasa.gov (secure)] |
Anonymous Coward User ID: 77443056 Canada 03/14/2019 12:43 PM Report Abusive Post Report Copyright Violation | ... Quoting: Anonymous Coward 77456542 Yes it does because it shows that the NASA thrust equation is simply stating mass flow rate is force. This is wrong. Wrong. You can't have "mass flow rate" without velocity. [link to www.grc.nasa.gov (secure)] I’m holding the weight between two finger. The weight is contacting my fingers and the hand space between the two fingers. I move one finger, the wieght moves away from the hand space between the two fingers and falls sliding down the finger I didn’t move. How did the wieght move away from my finger if the velocity was 0? Where’s the opposite force? Quoting: fuckingretardSo apparently you failed basic physics and never understood basic force diagrams even for simple cases, like rolling something off a ramp. [link to www.physics.usyd.edu.au] Got it. That doesn't change the fact that you're dead wrong and physics works just fine. But for the previous example if you simply let a weight go it will have no velocity at the moment you release it. Now you're trying to change the example since I proved you wrong. So you are just going to ignore the part where velocity was substituted out of the equation? Exit velocity is in the original equation, just because you try to substitute something else equal to it does not render the original equation invalid. The velocity of the reaction mass matters. You can't have "mass flow rate" without velocity. [link to www.grc.nasa.gov (secure)] I didn’t try, I did. Using a valid equation. The end result is that it doesn’t work because one equation is wrong. That equation is the nasa equation |
Anonymous Coward User ID: 77456542 Canada 03/14/2019 12:46 PM Report Abusive Post Report Copyright Violation | ... Quoting: Anonymous Coward 77456542 Yes it does because it shows that the NASA thrust equation is simply stating mass flow rate is force. This is wrong. Wrong. You can't have "mass flow rate" without velocity. [link to www.grc.nasa.gov (secure)] I’m holding the weight between two finger. The weight is contacting my fingers and the hand space between the two fingers. I move one finger, the wieght moves away from the hand space between the two fingers and falls sliding down the finger I didn’t move. How did the wieght move away from my finger if the velocity was 0? Where’s the opposite force? Quoting: fuckingretardSo apparently you failed basic physics and never understood basic force diagrams even for simple cases, like rolling something off a ramp. [link to www.physics.usyd.edu.au] Got it. That doesn't change the fact that you're dead wrong and physics works just fine. But for the previous example if you simply let a weight go it will have no velocity at the moment you release it. Now you're trying to change the example since I proved you wrong. So you are just going to ignore the part where velocity was substituted out of the equation? Exit velocity is in the original equation, just because you try to substitute something else equal to it does not render the original equation invalid. The velocity of the reaction mass matters. You can't have "mass flow rate" without velocity. [link to www.grc.nasa.gov (secure)] Velocity due to flow rate is described in the video. |
Dr. Deplorable Astromut Senior Forum Moderator 03/14/2019 01:09 PM Report Abusive Post Report Copyright Violation | ... Quoting: Dr. Deplorable Astromut Wrong. You can't have "mass flow rate" without velocity. [link to www.grc.nasa.gov (secure)] ... So apparently you failed basic physics and never understood basic force diagrams even for simple cases, like rolling something off a ramp. [link to www.physics.usyd.edu.au] Got it. That doesn't change the fact that you're dead wrong and physics works just fine. But for the previous example if you simply let a weight go it will have no velocity at the moment you release it. Now you're trying to change the example since I proved you wrong. So you are just going to ignore the part where velocity was substituted out of the equation? Exit velocity is in the original equation, just because you try to substitute something else equal to it does not render the original equation invalid. The velocity of the reaction mass matters. You can't have "mass flow rate" without velocity. [link to www.grc.nasa.gov (secure)] I didn’t try, I did. Using a valid equation. The end result is that it doesn’t work because one equation is wrong. That equation is the nasa equation Nope. The equation works just fine, substituting in a more complex formula for the velocity of the fluid does not change the fact that the result still varies with the velocity of the fluid. Adjusting exit velocity still reduces the force, you're just trying to obfuscate it by substituting a formula for the velocity of a fluid in a pipe for the exit velocity. Exit velocity equals Me * sqrt (gamma * R * Te) where Te = exit temperature R = gas constant gamma = specific heat ratio Me = mach number If I substitute the above equation into the original formula it doesn't change the fact that exit velocity still matters, I've just substituted in a formula that equals the same thing. |
syncro User ID: 75835116 United States 03/14/2019 01:13 PM Report Abusive Post Report Copyright Violation | |
LHP598 User ID: 77436004 United States 03/14/2019 01:43 PM Report Abusive Post Report Copyright Violation | There is no scientific proof of a spinning water ball Earth in a vacuum. There is no observable Earth curvature. No curvature then not a ball, not a ball then you cannot call the Earth a sphere. Quoting: Anonymous Coward 73852158 You mean none you'd accept. If you have to insist that you've won an Internet argument, you've probably lost badly. - Danth's Law |
Anonymous Coward User ID: 72810610 United States 03/14/2019 02:30 PM Report Abusive Post Report Copyright Violation | Grab two pairs of polarizing sunglasses Quoting: Anonymous Coward 72810610 Line them up and look directly above you into the sky when the sun is at 10 o clock relative to your position Rayleigh scattering predicts light will be polarized linearly when traveling through a spherical medium i.e. the atmosphere because of nitrogen/oxygen dipole transmittance. A jones vector matrix reduction can quickly show this Tell me what happens when you rotate the sunglasses perpendicular to each other. Come back here with your results.. I restate this because no one has addressed it and it at least proves atmosphere is spherical |
Fluffy Pancakes User ID: 77376617 United States 03/14/2019 03:12 PM Report Abusive Post Report Copyright Violation | Grab two pairs of polarizing sunglasses Quoting: Anonymous Coward 72810610 Line them up and look directly above you into the sky when the sun is at 10 o clock relative to your position Rayleigh scattering predicts light will be polarized linearly when traveling through a spherical medium i.e. the atmosphere because of nitrogen/oxygen dipole transmittance. A jones vector matrix reduction can quickly show this Tell me what happens when you rotate the sunglasses perpendicular to each other. Come back here with your results.. I restate this because no one has addressed it and it at least proves atmosphere is spherical That would be the same for either FE with a dome or Global model with an atmosphere wrapped around the ball, so I'm not sure why you want people to do this in this thread? Astro, the reason I put you on ignore is that you often post tons of videos, and aren't very gracious about conversation. And since I have very limited bandwidth, I am not interested in watching tons of videos, and I also don't like getting into protracted hostile altercations. My observations are MY observations. And I don't care to proselytize anyone. It just seems that people don't even want to let other people discuss things that they see that are not inline with what we are taught. There is no logical reason why discussion should be such an affront to anyone. The shape of the Earth shouldn't be such a difficult thing to prove. If it's a ball, there are plenty of things in space that should be able to show a clear video of it spinning without the use of CGI. It should be relatively simple according to all the things we are told are certain about space. In my daily life, the shape is irrelevant. Things are bad enough, there is no need to make anything up. ~Fluffy "Never interrupt an enemy in the process of destroying himself." Quercitin and zinc...Get it. Take it. Visit howbad.info...If you took the shot, for sure. |
Anonymous Coward User ID: 77275768 United States 03/14/2019 03:23 PM Report Abusive Post Report Copyright Violation | Yes it does because it shows that the NASA thrust equation is simply stating mass flow rate is force. This is wrong. Quoting: Anonymous Coward 77456542 Here's something that maybe, just maybe you'll understand.... Since you like FE university of youtube, Explain the movement of the water hose........ [link to www.youtube.com (secure)] Any objective person will conclude the flow of water is causing opposite reaction force that makes the hose move. Mass flow rate is force. This is high school physics. Can you rule out with evidence that it is not pushing off air? Utter complete Bullsh!t. 1 gallon of air(at sea level) is about 0.09 lbs. 1 gallon of water is about 9.0 lbs. The molecular density/mass of water is 100 times that of air. Pushing against air is insignificant and immaterial. If rocket thrust was from pushing off air, the forward air résistance would cancel that out. Get a high school physics book and READ IT! |
Anonymous Coward User ID: 73852158 United States 03/14/2019 03:42 PM Report Abusive Post Report Copyright Violation | A guy that was going to prove rockets work in a vacuum failed 3 times, he then put the rocket in a tube of air, put the tube in the vacuum chamber, rocket fired, he then said see it works, ha There are plenty of experiments that show combustion does not work in a vacuum, even with things that have their own oxidizer. The idea of rockets working by pushing off the combustion chamber walls is complete nonsense, the force would be pushing against all surfaces, sides front back top bottom except exit hole, thus negating any directional force. A spinning water ball Earth in a vacuum is beyond the pale of nonsense. |
Anonymous Coward User ID: 73852158 United States 03/14/2019 04:04 PM Report Abusive Post Report Copyright Violation | |
Dr. Deplorable Astromut Senior Forum Moderator 03/14/2019 04:08 PM Report Abusive Post Report Copyright Violation | Grab two pairs of polarizing sunglasses Quoting: Anonymous Coward 72810610 Line them up and look directly above you into the sky when the sun is at 10 o clock relative to your position Rayleigh scattering predicts light will be polarized linearly when traveling through a spherical medium i.e. the atmosphere because of nitrogen/oxygen dipole transmittance. A jones vector matrix reduction can quickly show this Tell me what happens when you rotate the sunglasses perpendicular to each other. Come back here with your results.. I restate this because no one has addressed it and it at least proves atmosphere is spherical That would be the same for either FE with a dome or Global model with an atmosphere wrapped around the ball, so I'm not sure why you want people to do this in this thread? Astro, the reason I put you on ignore is that you often post tons of videos, and aren't very gracious about conversation. Based on how you are addressing that AC, it seems you think that is me posting while not logged in. You had better read this post so that I may disabuse you of that mistaken notion. I do not use sock puppets and I do not make AC posts to try to get around your decision to put me on ignore. This is the one and only statement I will make about this, do not continue to talk to others as if they are me. They are not me and if you want to talk to me you know how to do so. As I said before, my participation in this thread and every other thread that isn't mine is rapidly drawing to a close. I will not allow you to go on pretending that I'm secretly still in these threads posting using sock puppets and if you persist in that behavior then there will be infractions coming your way. I frankly do not care if you fail to read this post because of your childish decision to ignore a moderator, the consequences you will reap will be your own for your short-sighted decision to ignore a mod. My observations are MY observations. And I don't care to proselytize anyone. It just seems that people don't even want to let other people discuss things that they see that are not inline with what we are taught. Quoting: PancakesIf I didn't want people to discuss things I would have simply removed the whole thread. It's posted by a banned user anyway, but I'm far more patient than you give me credit for and I am always slow to lay down bans and delete threads except in extreme violations. That said, I do tire of people who refuse to accept concrete answers backed up by proof and continue to repeat the same questions ad nauseum. It illustrates a lack of open mindedness and wastes everyone's time. The shape of the Earth shouldn't be such a difficult thing to prove. If it's a ball, there are plenty of things in space that should be able to show a clear video of it spinning without the use of CGI. Quoting: PancakesIt isn't difficult to prove and many such videos do exist, in fact there are new images of it taken every day by a variety of satellites, but you've already admitted you block my posts and refuse to watch such videos. So you can stop pretending that it hasn't been answered, the fact is you're just stubborn and refuse to accept any answer. Last Edited by Astromut on 03/14/2019 04:09 PM |