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REPORT ABUSIVE REPLY
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Message Subject
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Globe Earth debunked
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Poster Handle
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Dr. Deplorable Astromut |
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Post Content
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...Wrong. You can't have "mass flow rate" without velocity. [ link to www.grc.nasa.gov (secure)] ...So apparently you failed basic physics and never understood basic force diagrams even for simple cases, like rolling something off a ramp. [ link to www.physics.usyd.edu.au] Got it. That doesn't change the fact that you're dead wrong and physics works just fine. But for the previous example if you simply let a weight go it will have no velocity at the moment you release it. Now you're trying to change the example since I proved you wrong. Quoting: Dr. Deplorable Astromut So you are just going to ignore the part where velocity was substituted out of the equation? Exit velocity is in the original equation, just because you try to substitute something else equal to it does not render the original equation invalid. The velocity of the reaction mass matters. You can't have "mass flow rate" without velocity. [ link to www.grc.nasa.gov (secure)] I didn’t try, I did. Using a valid equation. The end result is that it doesn’t work because one equation is wrong. That equation is the nasa equation Nope. The equation works just fine, substituting in a more complex formula for the velocity of the fluid does not change the fact that the result still varies with the velocity of the fluid. Adjusting exit velocity still reduces the force, you're just trying to obfuscate it by substituting a formula for the velocity of a fluid in a pipe for the exit velocity. Exit velocity equals Me * sqrt (gamma * R * Te) where Te = exit temperature R = gas constant gamma = specific heat ratio Me = mach number If I substitute the above equation into the original formula it doesn't change the fact that exit velocity still matters, I've just substituted in a formula that equals the same thing.
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