A softball is hit at a 30 degree angle traveling 100 meters before being caught. At what speed did it leave the bat?

This is just a subtle thread to confuse you all

33.65 m/s give or take depending on the catchers height and the balls mass.

not enough info provided

Hey muggaphucka dis beez raycis mayhn..!sheeit, whay ain yoo said a bakkaball beez trablin???

Nunna yooz beez allowed in muh collij studen lounje...fo coluds onlee!

So the op was spot on that it is 33.6 m/s, now it's only the decimal significant figures that are up for debate.

I think op meant on Earth, not the ISS.

Yup, but I still say 5 and a half inches not 5.

Those figures matter you known

Improbable question, not enough valid information given... We can apply several principals for several different correct answers.

You don't provide enough information. Its a poorly phrased question by someone with little grasp on basic physics. You cannot estimate speed from exit angle and distance traveled. You would have to know how quickky it arrived. There is also the complication of drag, which I am guessing you aren't considering.

And for those of you who are saying that the ball leaves at zero, you are even dumber than OP. The ball remains in contact with the bat for some fraction of a second during which time the bat exerts a force on the ball causing it to accelerate quickly. Once the ball is no longer touching the bat, it starts to slow down... not speed up.

Common people... this is not rocket science.

This is a task that requires Galileo`s tool bag.

Looking at the answers, I misunderstood the question.

I think OP is referring to the ball used in a game called softball, not a light sponge ball.

I thought OP meant it was hit at 30 degrees to the left or right, but at the same height.

But I think Op meant 30 degree vertically, so it travelled in an arc.

Im a big winner!! Do I win a softball??

Don't know the answer, but...A hundred meters! That would be a homerun. Quite the swat with a softball!

Seems like there is enough information to calculate it since the speed of gravity would be a determining factor.

Is the bat African or European?

Just as a closing statement

Distance = (Initial velocity^2/9.8m/s^2)*Sin(2*30 degrees)

plug in distance then solve for initial velocity

100m = (Initial velocity^2/9.8m/s^2)*.866
100m /.866 = (Initial velocity^2/9.8m/s^2)
115.473m = (Initial velocity^2/9.8m/s^2)
115.473m * 9.8m/s^2 = Initial velocity^2
1131.6354m^2/s^2 = Initial velocity^2
33.6397 = Initial velocity

Last Edited by scimitar on 05/22/2017 11:12 AM

Depends... Is the Earth flat?