The Wet & Dry Moon Are Neologisms | |
Dr. Astro Senior Forum Moderator User ID: 1524705 United States 05/15/2013 11:31 PM Report Abusive Post Report Copyright Violation | So what's going on with the moon tonight? It's a waxing Gibbous? But my Wii game console for the weather channel shows that it's supposed to be a full moon tonight? What's up with that? Quoting: Anonymous Coward 38646296 I just saw the moon and it's waxing crescent, not gibbous. It should be about 30.8% full right now by my calculations. |
Dr. Astro Senior Forum Moderator User ID: 1524705 United States 05/15/2013 11:37 PM Report Abusive Post Report Copyright Violation | Well DVCMCM (OP) - from the hate and shills you are picking up I would say you are bringing them some fear. Quoting: Lemon keep up the good work. This^ Oh really? Show where my calculations are wrong. [link to dropcanvas.com] |
WindyMind User ID: 7244814 United States 05/15/2013 11:56 PM Report Abusive Post Report Copyright Violation | Ducks, I like ducks, white ducks, and brown ducks and baby ducks, ducks don't care, ducks just are wonderful. If Duck thinks something is strange about the moon then maybe there is. There is a new physicist saying unbelievable things like we don't revolve around the sun like has been thought. He says we spiral around the sun and who is it that says the sun may be spiraling around something as well? I like a new idea. Duck may be right you know. |
Anonymous Coward User ID: 20517650 United States 05/16/2013 12:03 AM Report Abusive Post Report Copyright Violation | |
Anonymous Coward User ID: 19648336 United States 05/16/2013 12:43 AM Report Abusive Post Report Copyright Violation | |
Dr. Astro Senior Forum Moderator User ID: 1524705 United States 05/16/2013 12:45 AM Report Abusive Post Report Copyright Violation | Ducks, I like ducks, white ducks, and brown ducks and baby ducks, ducks don't care, ducks just are wonderful. If Duck thinks something is strange about the moon then maybe there is. There is a new physicist saying unbelievable things like we don't revolve around the sun like has been thought. He says we spiral around the sun and who is it that says the sun may be spiraling around something as well? I like a new idea. Duck may be right you know. Quoting: WindyMind [link to www.godlikeproductions.com] He's wrong. So is the guy who claims we spiral in a vortex behind the sun instead of orbiting around it. In both cases you can calculate and predict where things should be and how they should look, it will disagree with ducky, but agree with reality. Last Edited by Astromut on 05/16/2013 12:50 AM |
Dr. Astro Senior Forum Moderator User ID: 1524705 United States 05/16/2013 12:53 AM Report Abusive Post Report Copyright Violation | I don't really do podcasts, I do read spaceflightnow, various astronomy blogs, and most importantly, journal articles. Right now though, celestial mechanics calculations occupy my astronomy time. For that I refer to very old books. Newcomb, Clemence, Hill, etc. |
#Geomagnetic_Storm# User ID: 39884526 United States 05/16/2013 01:59 AM Report Abusive Post Report Copyright Violation | And another great thread by Ducky! LMAO |
Anonymous Coward User ID: 1542840 United States 05/16/2013 02:43 AM Report Abusive Post Report Copyright Violation | |
DVCMCM (OP) User ID: 39920970 Italy 05/16/2013 02:46 AM Report Abusive Post Report Copyright Violation | Well DVCMCM (OP) - from the hate and shills you are picking up I would say you are bringing them some fear. Quoting: Lemon keep up the good work. This^ Oh really? Show where my calculations are wrong. [link to dropcanvas.com] Oh really? Show the math formula then... Lies Have Short Legs. - Last Edited by IWASTHERE on 05/16/2013 02:55 AM |
Ozicell User ID: 39868536 Australia 05/16/2013 02:57 AM Report Abusive Post Report Copyright Violation | (Dry Moon too) And it was introduced since 2005 only in the internet for trying to normalize that new phenomena we are living right now with that kind of Moon (sideways) on the Northern Hemisphere Regions where its not supposed to be seen. Quoting: DVCMCM The first sideways Moon was there in late 2007 only. Wrong. You cant find that kind of Moon configurations in any school books as an explanation (just because its not contemplated), in any family photo, movies before that date. Quoting: duckyWrong. [link to www.gutenberg.org] Page 163: "It is to be noticed that ab, the line which joins the cusps, is always perpendicular to the line directed to the sun, and the horns are always turned away from the sun; so that the precise position in which they will stand at any time is always predictable, and has nothing whatsoever to do with the weather." [the last bit in reference to the wet moon which superstition said affected the weather - yes the wet moon is normal and has nothing to do with the weather] And the Nasa's "explanation" is something of ridiculous with not any scientific formula to calculate it in the next timeframe periods. Quoting: DuckyWrong. There's half the equations needed, the other half are the equations for converting from equatorial coordinates to horizon coordinates which can be found in chapter 8 of the same book shown above. The entire set of equations needed are executed by this spreadsheet and you can see them at work for yourself: [link to dropcanvas.com] Now Dr. Astro, I am very surprised that you haven't taken into account ALL factors here!! You forgot to factor in - people standing on their heads, people lying on their left side and people lying on their right side!!!! To these people, the orientation of the moon does appear different! Lunatics can be found everywhere! LOL That which is - has already been, And what is to be - has already been. Quote: King Solomon. |
DVCMCM (OP) User ID: 39920970 Italy 05/16/2013 03:03 AM Report Abusive Post Report Copyright Violation | Astro's stuff: Don't you AUS dude agree with me? If not WHY? Write something good instead of blahblah parroting. . Last Edited by IWASTHERE on 05/16/2013 03:08 AM |
Dr. Acula Senior Forum Moderator User ID: 6860 United States 05/16/2013 03:07 AM Report Abusive Post Report Copyright Violation | |
DVCMCM (OP) User ID: 39920970 Italy 05/16/2013 03:13 AM Report Abusive Post Report Copyright Violation | Its good, his info is the best source for astronomy around. Quoting: Dr. Acula Believe it or not bro. Really? That guy also is saying that the Moon normally rotates itself several degrees per hour like a lancet clock from the Earth view even if you stand in the same latitude... . Last Edited by IWASTHERE on 05/16/2013 03:26 AM |
Itcouldbeaname User ID: 38669366 United States 05/16/2013 03:16 AM Report Abusive Post Report Copyright Violation | |
DVCMCM (OP) User ID: 39920970 Italy 05/16/2013 03:22 AM Report Abusive Post Report Copyright Violation | |
DVCMCM (OP) User ID: 39920970 Italy 05/16/2013 03:55 AM Report Abusive Post Report Copyright Violation | My ancient people probably knew that: ...probably not a Lunar Eclipse, neither a kind of Moon you can find in the Equatorial Regions only or a adapted fantasy design. - Last Edited by IWASTHERE on 05/16/2013 05:29 AM |
DVCMCM (OP) User ID: 39920970 Italy 05/16/2013 04:10 AM Report Abusive Post Report Copyright Violation | [link to youtu.be] Phidias (?), Sculpture from the East Pediment of the Parthenon, c. 448-432 B.C.E 'Three nights remained before Luna's [Selene the Moon's] bright horns would meet and form her orb; then when she shone in fullest radiance and with form complete gazed down upon the sleeping lands below, [the witch] Medea, barefoot, her long robe unfastened, her hair upon her shoulders falling loose, went forth alone upon her roaming way, in the deep stillness of the midnight hour [to make her magics]." - Ovid, Metamorphoses 7.179' - Last Edited by IWASTHERE on 12/28/2013 06:24 PM |
Anonymous Coward User ID: 32170796 Austria 05/16/2013 06:34 AM Report Abusive Post Report Copyright Violation | it may be missunderstanding, i noticed, that for americans wet moon (horned) and dry moon (upside down, only top visible) is normal, but in europe it's very rare sighting. don't forget, that there's not only northern-southern hemisphere, but also western-eastern. |
Hydra User ID: 39900128 Germany 05/16/2013 07:32 AM Report Abusive Post Report Copyright Violation | it may be missunderstanding, i noticed, that for americans wet moon (horned) and dry moon (upside down, only top visible) is normal, but in europe it's very rare sighting. don't forget, that there's not only northern-southern hemisphere, but also western-eastern. Quoting: Anonymous Coward 32170796 Don't forget "up and down" and "Left and right". Sorry Ösi, I don't get it. Do you want to tell us, that there is no east and west in America? :ndtbefore: . :ase26122019: Annular Solar Eclipse - December 26, 2019 - Kannur, Kerala, India |
Anonymous Coward User ID: 32170796 Austria 05/16/2013 07:42 AM Report Abusive Post Report Copyright Violation | |
Frank Frankson User ID: 24816411 United States 05/16/2013 08:01 AM Report Abusive Post Report Copyright Violation | How dare someone suggest that something isn't normal with the moon on a conspiracy theory forum. Last Edited by Frank Frankson on 05/16/2013 08:02 AM |
Hydra User ID: 39900128 Germany 05/16/2013 08:55 AM Report Abusive Post Report Copyright Violation | it may be missunderstanding, i noticed, that for americans wet moon (horned) and dry moon (upside down, only top visible) is normal, but in europe it's very rare sighting. don't forget, that there's not only northern-southern hemisphere, but also western-eastern. Quoting: Ösi 32170796 Don't forget "up and down" and "Left and right". Sorry Ösi, I don't get it. Do you want to tell us, that there is no east and west in America? :ndtbefore: east-west, up-down is relative terms darling. not even talking about yours knowledge about moon's "orbit". If "east-west" is a relative term, honey, why did you mention it in your first post to justify the allegedly "very rare sighting" of the Cheshire moon in Europe? The longitude of a location has only a marginal influence on the appearance of the moon - it's the latitude what matters. If you have a Cheshire or wet moon at a given location in the US, you had the same Cheshire moon at a location situated on the same latitude in Europe or all around the world some hours earlier. The longitudinal influence (time difference) is quite negligible. . :ase26122019: Annular Solar Eclipse - December 26, 2019 - Kannur, Kerala, India |
Dr. Astro Senior Forum Moderator User ID: 1524705 United States 05/16/2013 09:20 AM Report Abusive Post Report Copyright Violation | Well DVCMCM (OP) - from the hate and shills you are picking up I would say you are bringing them some fear. Quoting: Lemon keep up the good work. This^ Oh really? Show where my calculations are wrong. [link to dropcanvas.com] Oh really? Show the math formula then... Lies Have Short Legs. - It's all right there in the excel sheet Ducky. Take the center point of the moon in equatorial coordinates and add .25 degrees to declination (approximate radius of the moon - the latest version of my spreadsheet which also does calculations for the sun uses a more advanced function to find the exact apparent radius at any given point in time [link to dropcanvas.com] ). This will give you the equatorial coordinates of both the center point of the moon and the north point of the moon on the equatorial grid. Then calculate the position angle of the moon's bright limb relative to the north equatorial point. This is given by the equation seen in this video: Then to calculate for field rotation, convert the equatorial coordinates of both the center point and the north point to horizon coordinates. This is given by the formula. For azimuth, the formula is: tan(az)=(-sin(Hour angle in degrees +delta)*cos(declination))/(sin(declination)*cos(latitude)-cos(declination)*sin(latitude)*cos(hour angle in degrees+delta)) where delta is: tan(delta)=(p*cos(theta')*sin(hour angle in degrees))/((distance of moon in km/6378.14)*cos(declination)-p*cos(theta')*cos(hour angle in degrees)) For altitude the formula is: sin(altitude)=(sin(declination)*sin(latitude))/(cos(declination)*cos(latitude)*cos(hour angle in degrees)) Now once you have converted both the center point and north point to altitude and azimuth, take the difference of each (altitude and azimuth) between the north and center points to find delta alt and delta az. From there, calculate the angle of the line from the center point to north point relative to the horizon: arctan(delta alt/delta az) Then add the position angle of the moon and in order to express the resulting orientation angle of the moon relative to the horizon as I have (as an angle expressed as degrees from vertical from 0 to 90 degrees) follow the following formulae: IF(ANSWER>360,ANSWER-360,ANSWER)) = ANSWER 2 IF(AND(ANSWER 2>90,OR(ANSWER 2<180,ANSWER 2=180)),(90-ANSWER 2)+90,ANSWER 2) = ANSWER 3 =IF(AND(ANSWER 2=ANSWER 3,ANSWER 2>180,OR(ANSWER 2<270,ANSWER 2=270)),ABSOLUTE VALUE(180-ANSWER 2),ANSWER 3) = ANSWER 4 =IF(AND(ANSWER 4=ANSWER 2,ANSWER 2>270),(90-(ANSWER 2-180)+90),ANSWER 4) = Final answer and the apparent orientation of the moon relative to the horizon. |
Dr. Astro Senior Forum Moderator User ID: 1524705 United States 05/16/2013 04:08 PM Report Abusive Post Report Copyright Violation | Quoting: Dr. Astro Oh really? Show the math formula then... Lies Have Short Legs. - It's all right there in the excel sheet Ducky. Take the center point of the moon in equatorial coordinates and add .25 degrees to declination (approximate radius of the moon - the latest version of my spreadsheet which also does calculations for the sun uses a more advanced function to find the exact apparent radius at any given point in time [link to dropcanvas.com] ). This will give you the equatorial coordinates of both the center point of the moon and the north point of the moon on the equatorial grid. Then calculate the position angle of the moon's bright limb relative to the north equatorial point. This is given by the equation seen in this video: Then to calculate for field rotation, convert the equatorial coordinates of both the center point and the north point to horizon coordinates. This is given by the formula. For azimuth, the formula is: tan(az)=(-sin(Hour angle in degrees +delta)*cos(declination))/(sin(declination)*cos(latitude)-cos(declination)*sin(latitude)*cos(hour angle in degrees+delta)) where delta is: tan(delta)=(p*cos(theta')*sin(hour angle in degrees))/((distance of moon in km/6378.14)*cos(declination)-p*cos(theta')*cos(hour angle in degrees)) For altitude the formula is: sin(altitude)=(sin(declination)*sin(latitude))/(cos(declination)*cos(latitude)*cos(hour angle in degrees)) Now once you have converted both the center point and north point to altitude and azimuth, take the difference of each (altitude and azimuth) between the north and center points to find delta alt and delta az. From there, calculate the angle of the line from the center point to north point relative to the horizon: arctan(delta alt/delta az) Then add the position angle of the moon and in order to express the resulting orientation angle of the moon relative to the horizon as I have (as an angle expressed as degrees from vertical from 0 to 90 degrees) follow the following formulae: IF(ANSWER>360,ANSWER-360,ANSWER)) = ANSWER 2 IF(AND(ANSWER 2>90,OR(ANSWER 2<180,ANSWER 2=180)),(90-ANSWER 2)+90,ANSWER 2) = ANSWER 3 =IF(AND(ANSWER 2=ANSWER 3,ANSWER 2>180,OR(ANSWER 2<270,ANSWER 2=270)),ABSOLUTE VALUE(180-ANSWER 2),ANSWER 3) = ANSWER 4 =IF(AND(ANSWER 4=ANSWER 2,ANSWER 2>270),(90-(ANSWER 2-180)+90),ANSWER 4) = Final answer and the apparent orientation of the moon relative to the horizon. No response? So much for my calculations being a lie. I was telling the truth. |
Lemon User ID: 677476 United States 05/16/2013 04:14 PM Report Abusive Post Report Copyright Violation | "For amateur astronomers and photographers alike, each young Moon makes an inviting target. The sunlit part encircles the Moon’s night side, which is not fully dark but is bathed in sunlight reflected back toward the Moon from Earth. This earthshine theoretically gets brighter the closer the Moon is to new, except that it can easily be washed out by twilight. On rare occasions it has even been seen during a total solar eclipse." Seeking Thin Crescent Moons by Roger W. Sinnott *** No need to shill / hate. I have no interest in the game. **I'm all out of bubblegum |
Dr. Acula Senior Forum Moderator User ID: 75950 United States 05/16/2013 04:49 PM Report Abusive Post Report Copyright Violation | my guess is it proable started in the early 70's, but normal it is not. the times are here. my 99 year old grandma died in 1985... she always told folks the moon is like a bowl full of water... when that bowl of water turns right side up it empties and there will be a lot of rain... old folk tales and all... she talked about seeing it when she was a kid... its not a new thing... its been happening ever since the moon was in the sky. how and when did it get there? i dont know 100% for sure, dont care really lol but the upside down, wet moon, horned moon, Cheshire moon... whatever you want to call it... is not new... _______________________ |
Anonymous Coward User ID: 39919682 Germany 05/16/2013 05:02 PM Report Abusive Post Report Copyright Violation | it may be missunderstanding, i noticed, that for americans wet moon (horned) and dry moon (upside down, only top visible) is normal, but in europe it's very rare sighting. don't forget, that there's not only northern-southern hemisphere, but also western-eastern. Quoting: Anonymous Coward 32170796 agreed. i first saw the moon sideways after the chile quake in 2008. me and my friend were baffled for sure. and it is not that we didn't pay attention before... |
Dr. Astro Senior Forum Moderator User ID: 1638744 United States 05/16/2013 05:18 PM Report Abusive Post Report Copyright Violation | my guess is it proable started in the early 70's, but normal it is not. the times are here. I love how the claim gets older as the photos get older. It's normal and expected. [link to dropcanvas.com] |
DVCMCM (OP) User ID: 39935091 Italy 05/16/2013 05:22 PM Report Abusive Post Report Copyright Violation | |